Question

Round to nearest tenth and solve for x

Answer 1

Answer:

$\displaystyle 9,6$

Step-by-step explanation:

$\displaystyle \frac{x}{6,4} = csc\:42 \hookrightarrow 6,4cot\:42 = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x$

OR

$\displaystyle \frac{6,4}{x} = sin\:42 \hookrightarrow xsin\:42 = 6,4 \hookrightarrow \frac{6,4}{sin\:42} = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x$

Information on trigonometric ratios

$\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ$

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