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11111nata11111 [884]
2 years ago
9

Please help!

Mathematics
2 answers:
coldgirl [10]2 years ago
7 0

Answer:

Question 1 )

given ,

height of cylinder = 9 cm

diameter of cylinder = 10 cm

\dashrightarrow \: radius =  \frac{10}{5}  \: cm \\

now ,

Volume \: of \: cylinder = \pi \: r {}^{2} h \\  \\ substitutng \: the \: values \: of \: h \: and \: r \:  \\  \\ \dashrightarrow \:  \pi \:   \times  (\frac{10}{2} ) {}^{2}  \times 9 \\  \\ \dashrightarrow \: \pi \:  \times 25 \times 9 \\  \\ \dashrightarrow \: 225\pi \: cm {}^{3}

therefore ,

<u>option </u><u>(</u><u>C)</u> is correct.

______________________________________

______________________________________

Question - 2 )

dimensions of the rectangular prism are 2 × 3 × 4

Lateral \: surface \: area  = 2h(l + b) \\  \\ \dashrightarrow \: 2 \times 3(4 + 2) \\  \\ \dashrightarrow \: 6(6) \\  \\ \dashrightarrow \: 36 \: cm {}^{2}

hope helpful :D

Iteru [2.4K]2 years ago
6 0

The volume of the cylinder is 225 \rm cm^3  and the lateral surface area of the rectangular prism is 36 square cm.

It is given that the radius of the cylinder is 10 cm and height is 9 cm.

It is required to find the volume of the cylinder.

<h3>What is volume?</h3>

It is defined as a three-dimensional space enclosed by an object or thing.

We know the volume of a cylinder given by:

\rm V = \pi r^2 h

We have diameter = 10 cm

Radius r = 10/2 = 5 cm

and height h = 9 cm

Volume will be:

\rm V= \pi \times5^2 \times 9

V = 225π cubic cm

For the lateral surface area = 2h(l+b)

= 2×3(4+2)

= 36 square cm

Thus, the volume of the cylinder is 225 \rm cm^3  and the lateral surface area of the rectangular prism is 36 square cm.

Learn more about the volume here:

brainly.com/question/16788902

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cos(<em>x</em> + <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) - sin(<em>x</em>) sin(<em>y</em>)

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1/2 (cos(9<em>x</em>) - cos(<em>x</em>)) + 1/2 (cos(7<em>x</em>) - cos(3<em>x</em>)) = 0

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Recall the double angle identity for sine:

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Rewrite the equation again as

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<em />

(where <em>n</em> is any integer)

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