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1 year ago

What is the surface area of the Triangular Prism rounded to the nearest tenth?

Mathematics

2 answers:

Illusion [34]1 year ago

8 0

Answer:

C. 43.6

Step-by-step explanation:

you need to take the area of each shape

lets do the skinny triangles first on the top and bottom of this shape.

so to find the formula of triangle we need to do 0.5 * 1.26 * 5.3

because the formula of a triangle is half the base times height.

so we get 0.5 * 1.26 * 5.3 = 3.339

multiply it by two and we get 6.678

now lets find the area of the huge rectangle on the back/behind of the shape

3.3*5.3 = 17.49

now lets find the area of the two smaller rectangles

3.3 * 3.6 = 11.88

2.3 * 3.3 = 7.59

now lets add

6.678 + 17.49 + 11.88 + 7.59 = 43.638

round it to 43.6

snow_lady [41]1 year ago

7 0

I think the answer is C. 43.6

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Answer:

8 years approximately

The problem (I'm assuming is):

Solve $100e^{0.05t}=150$ .

I put a t in the problem where I suspected it in went.

Step-by-step explanation:

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Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do

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Answer:

$y = \frac{1}{3}x + 5$

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other: $m = - \frac{1}{m_{2} }$ , or equivalently, $m_{1} * m_{2} = -1$ .

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We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is $\frac{1}{3}$ .

To test whether this is correct, we can take first slope, $m_{1} = -3$ , and multiply it with the negative reciprocal slope $m_{2} = \frac{1}{3}$ :

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