1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Answer:
The answer is AB also i just took the test on edg and got it right
Step-by-step explanation:
A straight line or plane that touches a curve or curved surface at a point, but if extended does not cross it at that point is a tangent.