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2 years ago

(-6x + 3) + (X - 7) add linear expressions

1 answer:

3 0

-6x + 3 + x - 7...when ur adding expressions such as this, and there is a plus sign in between them, the parenthesis are not needed.

we now combine like terms...
-6x + x = -5x
3 - 7 = -4

and we are left with : -5x - 4 <==

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krek1111 [17]

Answer:

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Step-by-step explanation:

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2 years ago

Clarke has 2 1/2 gallons of juice. how many 1-pint containers can he fill? show your work and explain

Musya8 [376]

Answer:

12 cups

Step-by-step explanation:

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3 years ago

The figure shows a cylinder of diameter 12cm and height = 15cm. A hole in the shape of cone is bored into one of its end. If the

Lisa [10]

Answer:

$\bold{495\pi} \approx \bold{1555.088 cm^3}$

Step-by-step explanation:

There was no figure but the question is clear

Volume of a cylinder is given by the formula $\bold{\pi r^2h}\\$

where r is radius of base of cylinder, h is the height

Volume of a cone is given by $\bold{\frac{1}{3} \pi r^2 h}$

where r is the radius of base of cone, h is the height

The radius of the cylinder = $\frac{1}{2}$ (diameter) = $\frac{1}{2}$ (12) = 6cm

Height of cylinder = 15cm

Volume of cylinder $V_{cyl} = \pi (6)^2 15 = \pi (36)15 = \bold{540\pi}$

Radius of cone = $\frac{1}{2}$ (radius of cylinder) = $\frac{1}{2}$ (6) = 3 cm

Height of cone same as height of cylinder = 15cm

Volume of cone, $V_{cone} = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (3)^2 15 = \frac{1}{3}(9)15\pi = \bold{45\pi}\\$

Difference is the volume of the remaining solid

$V_{cyl} - V_{cone} = 540\pi - 45\pi = \bold{495\pi} \approx \bold{1555.088 cm^3}$

5 0

1 year ago

PLEASE ANSWERRRRRRRRRRRRRRRRRRRRRRRR

tekilochka [14]

Answer:

a=11, b=53

Step-by-step explanation:

y=ax+b

x=1, y=64 -> 64=a+b

x=2, y=75 -> 75=2a+b

75-64=a, a=11, b=53

All the other points obey this rule.

8 0

3 years ago

Read 2 more answers

How many real roots does a quadratic equation have if the discriminant is -3?

soldier1979 [14.2K]

$\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ y=\stackrel{\stackrel{a}{\downarrow }}{a}x^2\stackrel{\stackrel{b}{\downarrow }}{+b}x\stackrel{\stackrel{c}{\downarrow }}{+c} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\stackrel{\textit{no real roots}}{\textit{no solution}}\quad \checkmark \end{cases}$

6 0

2 years ago