We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.
First of all, we will find z-score corresponding to 38 and 56.
Now we will find z-score corresponding to 56.
We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is 
.
We can see that data point 38 is at mean as it's z-score is 0 and z-score of 56 is 3. This means that 56 is 3 standard deviation above mean.
We know that mean is at center of normal distribution curve. So to find percentage of data points 3 SD above mean, we will divide 99.7% by 2.
Therefore, approximately 
of lightbulb replacement requests numbering between 38 and 56.
Answer:
<em>i: </em>x=-2, x=1
<em>ii: </em>x=-1/2
Step-by-step explanation:
Quadratic form:
You solve <em>i </em>by using FOIL (First, Outside, Inside, Last) because it is a multiplication problem.
<em>"first"</em> would be 
, which would equal 
<em>"outside"</em> would be 
, which would equal 
<em>"inside"</em> would be 
, which would equal 
<em>"last" </em>would be 
, which would equal 
Now you need to combine the terms so that they are one after the other
Combine like terms, and you should get:
i Solution
<em>You need to get the variable by itself.</em>
<em>Subtract two from both sides</em>
<em>Add one to both sides.</em>
ii Solution
<em>Add all the terms.</em>
<u>Answer:</u>
<u>Answer:The chocolate are 0.0042 lighter than the stated on the label</u>
I hope this helps with you
40×4×4=640
b=20 h=4
using formula:
1/2×base×height
1/2×20×4=40
its says scale by factor 4:
b=80 h=16
using formula:
1/2×base×height
1/2×80×16=640
answer------>>>>640cm^2
