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Ierofanga [76]
2 years ago
10

A company makes steel rods shaped like cylinders. Each rod has a radius of 4 centimeters and a height of 20 centimeters. If the

company used 28,134.4cm cubed of steel, how many rods did it make?
Use 3.14 for\pi , and do not round your answer.
Mathematics
1 answer:
Tamiku [17]2 years ago
5 0
(One steel rod’s volume) = 3.14 x 4^2 x 20

= 1004.8cm^3

(Used steel) / (One steel rod’s volume) =

(Made steel rod’s number)

The answer is 28
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Wewaii [24]

Answer:

look at picture

Step-by-step explanation:

x: adult tickets

y: student tickets

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3 years ago
You are one of 55 people whose name will be drawn for a prize. What is the probability that your name will be drawn first?
suter [353]

  Your answer will be 1/55 or A because, at the beginning of the problem it states "you are one of 55 people" ((:

8 0
2 years ago
6+7=10<br>13+8=18<br>32+21=32<br>11+34=0<br>31+03=?​<br>process please
Stella [2.4K]

Answer:

6+7=13

13+8=21

32+21=52

11+34=46

31+03=34

Step-by-step explanation:

im not sure in the 31+03

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Setler79 [48]
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6 0
1 year ago
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.&lt;b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
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