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Nataly [62]
2 years ago
7

The Ksp of CaF2 is 5.3 mc003-1.jpg 10-9. What is the molar solubility of CaF2 in 0.050 M Ca(NO3)2?

Chemistry
1 answer:
faltersainse [42]2 years ago
4 0
<span>Calcium-fluoride and calcium-nitrite dissolve and dissociate as follows:
CaF₂(s) ⇄ Ca²⁺(aq) + 2 F⁻(aq)  Ksp = [Ca</span>²⁺] x ([F⁻])^2 = 5.3 x 10^-9
Ca(NO₃)₂(s) ⇄ Ca²⁺(aq) + 2 NO₃⁻(aq)  [Ca²⁺]₀ = [<span>Ca(NO₃)₂] = 0.050 M

If s is the molar solubility of</span><span> calcium-fluoride, then, at equilibrium, we can write:
[Ca²⁺] = s +</span><span>[Ca²⁺]₀ = s + 0.050 M
[F⁻]= 2s

5.3 x 10^-9 = (s + 0.050 M) x (2s)^2

S is very small compared to 0.050 M so the s inside the first brackets can be ignored:
</span>
5.3 x 10^-9 = (0.050 M) x (2s)^2 <span>
<span>5.3 x 10^-9 / 0.050 M = 4 x s^2
</span>1.06 x 10^-7 = 4 x s^2</span>
<span>1.06 x 10^-7 / 4 = s^2
2.65 x 10^-8 = s^2
s = √</span><span><span>2.65 x 10^-8
s = 1.63 x 10^-4</span>

The molar solubility of calcium-fluoride in 0.050 M of calcium-nitrite is 1.63 x 10 ^-4 moles / liter.</span>














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Decide which element probably has a boiling point most and least similar to the boiling point of cesium.
natka813 [3]

Answer:

Take a look at the attachment below

Explanation:

Take a look at the periodic table. As you can see, Rubidium is the closest element to Cesium, and happens to have the closest boiling point to Cesium, with only a difference of about 30 degrees.

Respectively, you would think that fluorine should have the least similarity to Cesium with respect to it's boiling point, considering it is the farthest away from the element out of the 4 given. This is not an actual rule, there are no fixed trends of boiling points in the periodic table, there are some but overall the trends vary. However in this case fluorine does have the least similarity to Cesium with respect to it's boiling point, a difference of about 1,546.6 degrees.

<em>Hope that helps!</em>

5 0
3 years ago
Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would s
Brrunno [24]

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This is because the lead nitrate solution which contains particles of lead will mix with the potassium iodide solution containing  particles of iodide. Upon mixing,the  lead particles  from the Lead nitrate solution combines with the  iodide particles from Potassium iodide and form two compounds, a yellowish solid precipitate called lead iodide and a white solid  precipitate called Potassium nitrate.

The formation of entirely two new compounds is known as the double displacement reaction and can be written in a chemical equation as  

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See similar answer here  :https://brainly.in/question/46262462

4 0
2 years ago
Read 2 more answers
How many moles are in 2.04 x 10^8 atoms of calcium?
I am Lyosha [343]

Answer:

2.0 moles

Explanation:

I hope this helps you a little bit at least the answer is 2.0 but if you want to review more stuff check the photos

7 0
2 years ago
How many grams of water vapor (H2O) are in a 10.2 liter sample at 0.98 atmospheres and 26ÁC? Show all work used to solve this pr
klio [65]
The answer is 7.33 g.

<span>To calculate this, we will use the the ideal gas law:
PV = nRT
where
P - pressure of the gas,
V - volume of the gas,
n - amount of substance of gas,
R - gas constant,
T - temperature of the gas.</span>

Since the amount of substance of gas (n) can be expressed as mass (m) divided by molar mass (M), then:

PV = RTm/M

It is given:

P = 0.98 atm

V = 10.2 l

T = 26°C = 299.15 K 

R = 0.082 l atm/Kmol (gas constant)

M (H2O) = 2Ar(H) + Ar(O) = 2*1 + 16 = 2 + 16 = 18g

m = ?

Since PV = RTm/M, then:

m = PVM/RT

m = 0.98 · 10.2 · 18 / 0.082 · 299.15 = 179.928/24.5303 = 7.33 g

6 0
3 years ago
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