1. A soluble salt can be prepared by reacting an acid with a suitable insoluble reactant including:
a metal
a metal oxide
a carbonate
3. I don’t know this one
4. A term base or glossary is a database containing single words or expressions related to a specific subject.
5. Strong acid is an acid that ionizes completely in aqueous solution. It always loses a proton (H+) when dissolved in water. Weak acid is an acid that ionizes partially in a solution. ... Because the rate of reaction depends upon the degree of dissociation αand strong acids have higher degrees of dissociation.
im not sure of the rest
Answer:
50 g Sucrose
Explanation:
Step 1: Given data
- Concentration of the solution: 2.5%
Step 2: Calculate the mass of sucrose needed to prepare the solution
The concentration of the solution is 2.5%, that is, there are 2.5 g of sucrose (solute) every 100 g of solution. The mass of sucrose needed to prepare 2000 g of solution is:
2000 g Solution × 2.5 g Sucrose/100 g Solution = 50 g Sucrose
Answer:
The molarity of a solution is 2.5 M
Explanation:
Molarity is a concentration unit that describes how much of a solution is dissolved in solution.
Molarity of a solution can found by using the formula,
Molarity (M) = (moles of solute)/(Liters of Solution).
Given, mass of Sodium = 114.95 grams.
Volume of water = 2 L.
Here, Sodium is solute as it is dissolved in water, which is the solvent.
Moles of Sodium(solute) can be found by using the formula,
Number of Moles = mass/Molecular weight.
mass of Sodium = 114.95 grams.
Molecular weight = 22.989 grams
Number of Moles of Sodium(solute) =114.95/22.989 = 5.
Substituting the values in the formula, we get,
M = 5/2 = 2.5 M
Answer:
[Br₂] = 1.25M
Explanation:
2NO (g) + Br₂ (g) ⇄ 2NOBr (g)
Eq 0.80M ? 0.80M
That's the situation told, in the statement.
Let's make the expression for Kc
Kc = [NOBr]² / [Br₂] . [NO]²
Kc = 0.80² / [Br₂] . [0.80]²
0.80 = 1 / [Br₂]
[Br₂] = 1 / 0.80 → 1.25
Answer:
When atoms are excited they emit light of certain wavelengths which correspond to different colors. Each element produces a unique set of spectral lines. Since no two elements emit the same spectral lines, elements can be identified by their line spectrum.
Explanation:
