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Alex787 [66]
3 years ago
15

What is true volume of the solids

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

The first one, i.e., a)28cm^3

Hope it helped you!


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After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos
igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P  and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}

and we found the distance PQ and QA

; d_{PQ}=\sqrt{125}, d_{QA}=12

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0
3 years ago
Which number line shows the solution to 5 + (−5)?
alex41 [277]

Answer:

first one is A  and the second one is B.

Step-by-step explanation:

7 0
3 years ago
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If f(x) = 4x-9, evaluate f(3) <br>I need HELP ASAP!!!!!!!!!!!​
seropon [69]

Answer:

substitute 3 as in x:

4(3)-9

= 12-9

= 3

Hope this helped - have a nice day & be safe

8 0
3 years ago
How do you find the area of the shaded sector of the circle? The radius is 10in and the sector is 45 degrees
Step2247 [10]

Given:

Radius of the circle = 10 in

Central angle of the sector = 45 degrees

To find:

The area of the sector.

Solution:

Area of a sector is

A=\dfrac{\theta}{360^\circ}\pi r^2

Where, \theta is the central angle in degrees.

Putting r=10 and \theta=45^\circ, we get

A=\dfrac{45^\circ}{360^\circ}\pi (10)^2

A=\dfrac{1}{8}\pi (100)

A=12.5\pi

Therefore, the area of the sector is 12.5π sq. inches.

7 0
3 years ago
NEED HELP EMERGENCY ‼️
cestrela7 [59]

Answer:

A. Reflect across the y-axis

Step-by-step explanation:

if the negative sign was outside the radical then it would've been a reflection on the x-axis.

6 0
3 years ago
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