3 years ago

Please show steps and show restrictions

1 answer:

5 0

$\dfrac{x^2+7x+12}{x^2-x-12}\\\\=\dfrac{x^2 +3x+4x +12}{x^2 -4x+3x-12}\\\\=\dfrac{x(x+3)+4(x+3)}{x(x-4)+3(x-4)}\\\\=\dfrac{(x+4)(x+3)}{(x-4)(x+3)}\\\\=\dfrac{x+4}{x-4}\\\\\text{Restrictions:}~ x\neq 4 ,~ x\neq -3$

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1.16667

Step-by-step explanation:

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4 years ago

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Answer:

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3 years ago

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Softa [21]

Answer:

Step-by-step explanation:

v = the original speed of the cruise

d = 225 km the distance passed

t = d/v = 225/v the total time of the travel

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Look at the images to see the solved equation

7 0

3 years ago

Which is greater? 4 tenths and 2 hundredths or 2 tenths and 4 hundredths

Orlov [11]

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Hope this helps.

8 0

4 years ago

PLLLLLLZZZZ HELP!! MULTIPLE CHOICE!!

liubo4ka [24]

First, set 2x+7 equal to 3x-7 since they are the same angle due to the parallel lines.

2x+7=3x-7
x=14

Then, since 2x+7 and 12y+1 equals 180, put it together to find y:

(2x+7)+(12y+1)=180
(2(14)+7)+(12y+1)=180
12y+1=145
12y=144
y=12

So, x=14 and y=12. Your answer should be C!

5 0

3 years ago