Choices: <span>A. 16/9
B. 4/3
C. 32/9
D. 64/27</span>
Given:
number of pints used for larger chest = 16 pints
number of pints used for smaller chest = 9 pints
Ratio of the volume of the larger chest compared to the smaller chest.
We will use the number of pints used in lieu of the volume of each chest.
16 / 9 is the ratio. Choice A.
Answer:
The answer is below
Step-by-step explanation:
a)Given that the length of fencing available is 400 yards. This means that the perimeter of the rectangle is 400 yards.
the perimeter of a rectangle is given as:
Perimeter = 2(length + width) = 2(l + w)
Hence;
400 = 2(l + w)
200 = l + w
l = 200 - w
The area of a rectangle is given as:
Area = length × width
Area = (200 - w) × w
Area = 200w - w²
b) For a quadratic equation y = ax² + bx + c. it has a maximum at x = -b/2a
Hence, for the area = 200w - w² a=-1, b = 200, the maximum width is at:
w = -b/2a = -200/2(-1) = -200/-2 = 100
A width of 100 yard has the largest area
c) l = 200 - w = 200 - 100 = 100 yards
Area = l × w = 100 × 100 = 10000 yd²
The maximum area is 10000 yd²
A cardboard box rests on the floor of an elevator. The box has a mass m = 3.75 kg and the elevator has an upward acceleration of a
Part a. Select the Free Body Diagram for the system
Part b. Write an expression for the sum of the forces actinv on the box in the y direcion, given that up is the positive y direction. Your answer should be in terms of FN, m, g.
Part c. Write an expression for the normal force FN, that the block experiences in terms of the elevator's accelaration, the block's mass and the accelaration of gravity
Part d. If the elevator's accelaration has a magnitude of g in the downward direction, what would the normal force FN1 be in Newtons? (Numerical value)
Part e. If the elevator's accelaration had a magnitude of g in the upward direction, what would the normal force FN2 ve in Newtons? (Numerical value)
