Since Qp>Kp , the reaction is not at equilibrium.
<h3>What is the equilibrium constant?</h3>
The equilibrium constant shows the extent to which reactants are converted into products.
Now we have to obtain the Qp as follows;
Qp =[CH3OH]/[CO] [H2]^2
Qp = 0.265/(0.265) (0.265)^2
Qp = 14.2
Now we know that Kp = 6.09×10−3, Since Qp>Kp , the reaction is not at equilibrium.
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The energy that an object has is moving
The balanced equation for the reaction is as follows;
Ca(OH)₂ + 2HBr --> CaBr₂ + 2H₂O
stoichiometry of Ca(OH)₂ to HBr is 1:2
number of Ca(OH)₂ moles reacted - 0.10 mol/L x 0.1000 L = 0.010 mol
Number of HBr moles added - 0.10 mol/L x 0.4000 = 0.040 mol
1 mol of Ca(OH)₂ needs 2 mol of HBr for neutralisation
therefore 0.010 mol of Ca(OH)₂ needs - 0.010 x 2 = 0.020 mol of HBr to be neutralised
but 0.040 mol of HBr has been added therefore number of moles of HBr in excess - 0.040 - 0.020 = 0.020 mol
then pH of the medium can be calculated using the excess H⁺ ions
HBr is a strong acid therefore complete ionization
[HBr] = [H⁺]
[H⁺] = 0.020 mol / (100.0 + 400.0 mL)
= 0.020 mol / 0.5 L
= 0.040 mol/L
pH = -log[H⁺]
pH = - log [0.040 M]
pH = 1.40
pH of the medium is 1.40
Answer:
vapour pressure I's crushing the bottle
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