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3 years ago

8

According to Bohr's Model, which one is correct about a transition from n=2 to n=1 in a hydrogen atom?

1 answer:

klio [65]3 years ago

6 0

When an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

<h3>What happen in transition from n= to n=1?</h3>

During transition from n=2 to n=1 in a hydrogen atom, the electron emits energy in the form of photon. We know that when electron absorb energy, it moves from lower level to higher level and vice versa.

So we can conclude that when an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

Learn more about transition here: brainly.com/question/1101400

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Where do red pandas live?

Degger [83]

Answer:

Red pandas live in the Eastern Himalayas in places like China, Nepal, and Bhutan . They spend most of their time in trees. Their semi-retractable claws help them move easily from branch to branch.

Explanation:

my answer would be A

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1 year ago

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The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr

GREYUIT [131]

Answer:

The $K_b$ expression for the weak base equilibrium is:

$K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

Explanation:

$(CH_3)_3N(aq)+H_2O(l)\rightlefharpoons (CH_3)_3NH^++OH^-(aq)$

The expression of the equilibrium constant of base $K_c$ can be given as:

$K_c=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N][H_2O]}$

] $K_b=K_c\times [H_2O]=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

As we know, water is pure solvent, we can put $[H_2O]=1$

$K_b=K_c\times 1=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

So, the the $K_b$ expression for the weak base equilibrium is:

$K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

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3 years ago

Hatshy [7]

A. isotopes only hve different mass which is caused by additional/lesser neutron. protons and electrons number are fixed

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3 years ago

Balance the following half-reaction: (acidic) VO2+(aq) → V3+(aq) Express your answer as a half-reaction. Identify all of the pha

ivolga24 [154]

Answer:

The balanced half reaction in an acidic medium is :

$VO^{2+}(aq)+2H^+(aq)+e^-\rightarrow V^{3+}(aq)+H_2O(l)$

Explanation:

$VO^{2+}(aq)\rightarrow V^{3+}(aq)$

While balancing the half-reaction in an acidic medium, we will first balance oxygen atoms by adding water:

1) Adding 1 water molecule on product side to balance oxygen atoms.

$VO^{2+}(aq)\rightarrow V^{3+}(aq)+H_2O(l)$

Now balance hydrogen atom by adding $H^+ ions$ .

2) Adding 2 hydrogen ions on reactant side to balance hydrogen atoms.

$VO^{2+}(aq)+2H^+(aq)\rightarrow V^{3+}(aq)+H_2O(l)$

Now balance the charge adding electrons on the side where positive charge is mor.

3) Adding 1 electrons on reactant side to balance charge of the overall reaction:

$VO^{2+}(aq)+2H^+(aq)+e^-\rightarrow V^{3+}(aq)+H_2O(l)$

The balanced half reaction in an acidic medium is :

$VO^{2+}(aq)+2H^+(aq)+e^-\rightarrow V^{3+}(aq)+H_2O(l)$

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3 years ago

Which of these describes how traits are shown on a branching tree diagram?

Sophie [7]

Answer:

D- Traits higher on the tree developed before traits lower on the tree.

Explanation:

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4 years ago

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