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12345 [234]
3 years ago
15

The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr

ium that occurs in an aqueous solution of trimethylamine:
Chemistry
1 answer:
GREYUIT [131]3 years ago
6 0

Answer:

The K_b expression for the weak base equilibrium is:

K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}

Explanation:

(CH_3)_3N(aq)+H_2O(l)\rightlefharpoons (CH_3)_3NH^++OH^-(aq)

The expression of the equilibrium constant of base K_c can be given as:

K_c=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N][H_2O]}

]K_b=K_c\times [H_2O]=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}

As we know, water is pure solvent, we can put [H_2O]=1

K_b=K_c\times 1=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}

So, the the K_b expression for the weak base equilibrium  is:

K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}

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