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victus00 [196]
3 years ago
13

When you bundle ten tens together they make 100, or a hundred

Mathematics
2 answers:
Ket [755]3 years ago
8 0
100 is your answer!!!!!!
BartSMP [9]3 years ago
4 0
What exactly are you asking? 100 and a hundred are the same thing lol
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7x-3y=-12. Name 2 possible answers for (x,y)
anzhelika [568]

Answer:

x = (-12/7 , 0)

y= (0,4)

Step-by-step explanation:

Plug y=0 into the equation and solve the resulting equation 7x=−12 for x

7x = -12

/7      /7

x = -12/7     and y =0

Plug x=0 into the equation and solve the resulting equation −3y=−12 for y

-3y = -12

/-3     -3

Y = 4        and X = 0

6 0
2 years ago
Find f(-5) of f (x) = x + 1<br> 1) 4<br> 2) 5<br> 6) 6
Alex
F(-5) just means that your substituting the number -5 for every x value. So if you have x+1 this would be -5+1 which is -4
7 0
3 years ago
What is 36:39 in simplest form
vova2212 [387]
12:13

Hope that helped!
8 0
3 years ago
Read 2 more answers
a coin collector has 36 dimes and nickels with a total face value of $2.80. they are actually worth a lot more. how many of each
Juliette [100K]

Answer:

16 nickels and 20 dimes

Step-by-step explanation:

16x5=80

20x10=200

80+200=280

280 cents = $2.80

8 0
3 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
2 years ago
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