Arrange the following bonds in order of increasing ionic character. assign number 1 as the highest and 6 as the lowest. a. carbo
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Answer: The concentrations of A , B , and C at equilibrium are 0.1583 M, 0.2583 M, and 0.1417 M.
Explanation:
The reaction equation is as follows.
Initial : 0.3 0.4 0
Change: -x -x x
Equilbm: (0.3 - x) (0.4 - x) x
We know that, relation between standard free energy and equilibrium constant is as follows.
Putting the given values into the above formula as follows.
x = 0.1417
Hence, at equilibrium
- [A] = 0.3 - 0.1417
= 0.1583 M
- [B] = 0.4 - 0.1417
= 0.2583 M
- [C] = 0.1417 M