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lyudmila [28]
3 years ago
6

In order to be considered science, something must be

Chemistry
1 answer:
Lynna [10]3 years ago
8 0
Some measure of examining information
You might be interested in
I have a balloon that can hold 125,000 mL of air. If I blow up this balloon with 3 moles of oxygen gas at a
matrenka [14]

Answer:

234.35 °C

Explanation:

Given data:

Volume of balloon = 125000 mL

Moles of oxygen = 3 mol

Pressure = 1 atm

Temperature = ?

Solution:

Formula:

PV = nRT

P = Pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

Volume of balloon = 125000 mL × 1 L /1000 mL

Volume of balloon = 125 L

Now we will put the values:

Ideal gas constant = R = 0.0821 atm.L/mol.K

PV = nRT

T = PV/nR

T = 1 atm × 125 L/  0.0821 atm.L/mol.K × 3 mol

T= 125  /0.2463 /K

T = 507.5 K

K to °C

507.5 K - 273.15 = 234.35 °C

4 0
3 years ago
From which plant can benzoic acid be obtained from?​
Sergeeva-Olga [200]

Explanation:

styrax benzoin is what benzoic acid is obtained from

7 0
4 years ago
Multiple Questions, Brainliest and 98 points to whoever answers all questions correctly
otez555 [7]

<u><em>Question 1</em></u>

The average atomic  mass  of element  is  84.66

<u>calculation</u>

Average  atomic mass is  of an element is the sum of masses of its isotope each  multiplied by its  natural  abundance.

that  is.

[(50.50 x  83.75) /100]   + [( 30.25 x 84.45)/100] + [(,9.25 x 87.40)/100]

=  42.29  +25.55 +16.82=  84.66



<u><em>Question 2</em></u>

fill the table

symbol    element    protons    neutrons   Electrons   mass No    Atomic No

Cs-133    cesium         55              78            55               133                55

Na-23      sodium         11                12            11                  23                  11

Ne 22       Neon           10              12            1 0                  22                  10        

Au -197     Gold            79             118            79                197                  79




<u><em>Question 3</em></u>

The moles of tungsten   that are  in  93.50  grams are 0.509  moles


moles=  mass/molar mass

 molar mass  of  tungsten  = 183.84 g/mol

moles  is therefore=  93.50  g/ 183.84  g/mol=  0.509  moles




<em><u>question  4</u></em>

CO2  molecules at STP  are 1.547 x10^23  molecules

 Step  1:  find the  moles of CO2

At  STP    1 mole of a gas= 22.4 l

                                    ?  =5.75 L

by cross multiplication

=  (5.75 L x 1 mole)/ 22.4 L= 0.257 moles

Step 2:  use the Avogadro's constant  to calculate the number of molecule

that is  1  moles = 6.02 x10^23 molecules

         0.257 moles= ? molecules

by  cross  multiplication

=(0.257 moles x 6.02  x 10^23) / 1 mole  = 1.547 x10^23  molecules



<u><em>question 5</em></u>

The number of calcium  atoms  is 3.82 x10^24  atoms

Step 1:  find the moles  of   calcium

= 253.50 g /40 g/mol= 6.34  moles


Step 2:  use the Avogadro's  law  to calculate the number of atoms.

that is   1 mole= 6.02 x 10^23 atoms

             6.34  moles=  ?  atoms

=6.34 x 6.02 x10^23  = 3.82  x10^24 atoms




<u><em>Question   6</em></u>

mass  in grams  of  NiBr2   is   126.97  grams

Step  1:  by use of  Avogadro's  law  constant  calculate  the  number  of moles


that  is  1 mole = 6.02 x 10^23

                 ?   =   3.50 x  10^23

by  cross  multiplication

= (1  mole  x 3.50  x10^23) /  6.02  x10^23 =0.581 moles

step 2:  calculate the  mass

mass =moles  x  molar mass

=  0.581 moles  x218.53 g/mol = 126.97 grams



 <u><em>Bonus question</em></u>

The molecules of water=  1.00  x10^26 molecules


  calculation

convert liters into  ml

= 3 x 1000  =  3000 ml

find the mass of  water

=  density  x volume

=3000  x0.998  2994  grams

find  the moles of water=mass/molar  mass

= 2994  g/  18  g/mol= 166.33 moles

Use  Avogadro's constant  to  calculate the molecules  of water

that is  1 mole=  6.02 x10^23  molecules

         166.33 moles= ? molecules

= (166.33 moles x6.02 x10^23 molecules) / 1 mole  =  1.00  x10^26  molecules

3 0
3 years ago
Read 2 more answers
A tank contains an ideal gas mixture of 5 g of O2 and 8 g of CO2 at 160kPa and specified temperature. If O2 were separated from
erica [24]

Answer:

74 or 74 kPa.

Explanation:

Hello,

In this case, based on the initial information, it is seen that the oxygen and the carbon dioxide form the mixture at 160 kPa, thus, by isolating the oxygen, its pressure will be equal to its initial partial pressure because it gets isolated, hence, we compute its molar fraction as:

x_{O_2}=\frac{5gO_2*\frac{1molO_2}{32gO_2} }{5gO_2*\frac{1molO_2}{32gO_2} +8gCO_2*\frac{1molCO_2}{44gCO_2} } =0.46

Therefore, its initial pressure turns out:

p_{O_2}=160kPa*0.46=73.9kPa

Such pressure will be the oxygen's pressure once it is isolated. Finally, considering the request, the answer will be just 74 (by rounding to the nearest integer and without units).

Best regards.

8 0
3 years ago
Write formulas for the binary ionic compounds formed between the following elements: a. Potassium and iodine b. Magnesium and ch
lianna [129]

i think it's B Magnesium and chlorine



5 0
3 years ago
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