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Sergeu [11.5K]
2 years ago
8

Why some aqutatic plants float an water give reason science subjects class 4​

Physics
1 answer:
VikaD [51]2 years ago
7 0
This is because leaves have air in the spaces between cells, which helps them collect CO2 gas from their environment to use in photosynthesis.
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A metal sphere has a charge of +10C. What is the net charge after 8.0 x 10^13 electrons have been placed on it?
masya89 [10]

Answer: 9.9999872 C

Explanation: In to answer this question we have to use the charge of the electron, that is eqaul to -1.6*10^-19 C.

After that, we have to calculate the charge given by 8.0*10^13 electrons, then we an additional charge of: 8.0*10^13 * -1,6*10^-19 C=1.28*10^-5C

Finally the net charge of the metal sphere, initially charged by +10C is:

10C-1.28*10^-5C=9.9999872 C

3 0
4 years ago
Find the resistance of a stereo: current is 7 A voltage is 49 V.
pochemuha

Answer:

R = 7 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance. In this way, we have the following equation.

V = I*R

where:

V = voltage = 49 [V] (units of volts)

I = current = 7 [amp] (amperes)

R = resistance [ohms]

Now clearing R.

R =V/I

R = 49/7

R = 7 [amp]

5 0
4 years ago
How does a rubber band obey the law of conservation of energy?
katovenus [111]
None of the energy is created nor destroyed
6 0
4 years ago
Determine the speed
Paraphin [41]
Calculating the average speed is simple using the formula <span>speed = distance/time</span>
3 0
4 years ago
You are designing a ski jump ramp for the next Winter Olympics. You need to calculate the vertical height h from the starting ga
Evgen [1.6K]

Answer:

h = 40.37 m

Explanation:

We will apply the law of conservation of energy to the skier in this case, as follows:

Energy\ of\ skier\ at\ the\ gate = Energy\ of\ Skier\ at\ the\ end\\P.E + K.E_{i} = K.E_{f} - W_{friction}\\mgh + \frac{1}{2}mv_{i}^2 = \frac{1}{2}mv_{f}^2 - W_{friction}\\\\mgh = \frac{1}{2}m(v_{f}^2-v_{i}^2) - W_{friction}

where,

m = mass of skier = 77 kg

g = acceleration due to gravity = 9.81 m/s²

vf = final speed = 30 m/s

vi = initial speed = 2 m/s

W_friction = Work done by friction and air resistance = 4000 J

Therefore,

(77\ kg)(9.81\ m/s^2)h = \frac{1}{2}(77\ kg)[(30\ m/s)^2-(2\ m/s)^2] - 4000\ J\\\\h = \frac{34496\ J - 4000\ J}{755.37\ N}\\\\

<u>h = 40.37 m</u>

5 0
4 years ago
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