 Find the equation of the line that is perpendicular to 4 x + 3 y = 5 and goes through the point (3, –3)
1 answer:
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We are given original equation:
We need to find the enter and radius of a circle using the completing the square method.
The steps are as following :
Step 1 [original equation]: x^2 − 10x + y^2 + 12y = 20 .
Step 2 [group like terms]: (x^2 − 10x) + (y^2 + 12y) = 20
Step 3 [complete the quadratics]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 20 + (25 + 36).
Step 4 [simplify the equation]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 64.
Step 5 [factor each quadratic]: (x − 5)^2 + (y + 6)^2 = 8^2
Step 6 [identify the center and radius]: Center = (5, −6) Radius = 8.
<h3>Step 6 is incorrect.</h3><h3>The center should be (5,-6).</h3><h3> Replace − 5 with + 5 and replace + 6 with − 6.</h3>Answer:
Step-by-step explanation:
Given
Change: -4, 7, -7 and 0
Required
Compare them
From the list of given options, we can observe that the inequality < is used in all options.
This implies that we arrange from least to highest
The least is -7
Then, -4
Then 0
And lastly, 7
So, we have: