Answer: An amount of 
heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.
Explanation:
Given: mass of lead = 4.64 kg
Convert kg into grams as follows.
The standard value of specific heat of lead is 
.
Formula used to calculate heat is as follows.
where,
q = heat energy
m = mass of substance
C = specific heat of substance
= change in temperature
Substitute the value into above formula as follows.
Thus, we can conclude that heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.
Answer:
The liquid collected during distillation when the evaporated substance condenses. A separation technique that uses evaporation to separate substances. The mixture is heated so that one substance evaporates. The vapour is collected and condenses into a liquid.
Answer:
On the left side of calcium atom.
Explanation:
There are two dots are present on the left side of calcium atom which represents the unpaired electrons present in the outermost shell. This structure is presented by Lewis in order to show the number of unpaired electrons in the atom. if the calcium atom loses these two electron during a chemical reaction so the two dots disappear and the calcium atom is now stable.
Answer: N5 + H4 and then do 13.5 * 17.8 then solve so 240.3 divided by 9
Your answer is 26.7 Pretty sure
Explanation: (study)
Answer:
Concentration of solution B is
Explanation:
Solution A: Total volume of solution A = (9.00+1.00) mL = 10.00 mL
According to law of dilution,
where and are initial and final concentration respectively. and are initial and final volume respectively.
Here = , = 1.00 mL, = 10.00 mL
So, =
So, concentration of solution A =
Solution B: Total volume of solution B = (2.00+8.00) mL = 10.00 mL
Similarly as above, =
So, concentration of solution B =
Explanation:
Hope this helps:)
