Answer:
Explanation:
i would say not d im not fully sure but id say c
Answer:
11.54 M
Explanation:
In this case, all we have to do is to apply the following expression:
M = n/V
M: molarity
n: moles
V: volume of solution in liters
In this case, we can assume that the volume of water will be the volume of solution. This is because the problem is not specifing if the moles of AgNO3 are liquid or solid, so we can make a safe assumption of the volume.
Using the expression above we have:
M = 5.54 / 0.48
M = 11.54 M
This is the molarity of solution
Answer:
7.23 J
Explanation:
Step 1: Given data
- Mass of graphite (m): 566.0 mg
- Initial temperature: 5.2 °C
- Final temperature: 23.2 °C
- Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹
Step 2: Calculate the energy required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)
Q = 7.23 J
