Find an equation for this I WILL MARK BRAINLIEST AND GIVE THANKS

Mathematics

1 answer:

Reika [66]2 years ago

6 0

Answer:

$\displaystyle Dependency\:[Infinitely\:Many\:Solutions]$

Explanation:

In the bottom equation, moving $\displaystyle -2x$ to the oppocite side will give you the linear standard equation above it, therefore numerous solutions will occur.

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Find the 7th term of the geometric sequence a3 =128,r=-1/4

kenny6666 [7]

Answer:

Step-by-step explanation:

The general formula for this sequence is a(n) = a(1)*(-1/4)^(n - 1). We don't yet know a(1).

If a(3) = 128, then 128 = a(1)*(-1/4)^(3 - 1), or

128 = a(1)*(1/16)

and so a(1) = 128/16

resulting in the specific formua a(n) = 8(-1/4)^(n - 1)

Now let's find a(7):

a(7) = 8(-1/4)^1 * (-1/4)^(6)

a(7) = 8(-1/4)^7

7 0

3 years ago

X plus 1/3 equals nine enter your answer in the box in simplest form

LekaFEV [45]

$= > x + \frac{1}{3} = 9$

$\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}$

$= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}$

Hence,

$Value \: \: \: of \: \: x \: \: is \: \frac{26}{3} \: \: \: or \: \: \: 8. \bar{6}$