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Yanka [14]
3 years ago
5

I’d appreciate the help! :)

Chemistry
1 answer:
Musya8 [376]3 years ago
4 0

Answer:

i

Explanation:

༒۝♥SOHAM♥۝༒꧂is shdkdof༒꧂unless

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Urea, a compound formed in the liver, is one of the ways humans excrete nitrogen. The Lewis structure for urea is H N H H C H O
yanalaym [24]

Answer:

The nitrogens are both sp3 hybridized. Their  bonds are formed by sp overlaps. The carbon and oxygen are sp2 hybridized. The double bond with oxygen is produced by a sp2 overlap to form the sigma component and a probital overlap to form the pi component. The bonds with hydrogen are formed by sp2 overlaps.

Explanation:

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3 years ago
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Georgia [21]

Answer:

Elements

Explanation:

The  <u> elements</u> which are represented by a single uppercase letter, or represented by an uppercase letter followed  by a lowercase letter. This tells you the types of <u>elements</u> in the compound.

Elements are one of the simplest chemical substances that cannot be decomposed in a chemical reaction or by any chemical means. They are made up of small indivisible particles called atoms, all having the same number of protons.

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One way to limit iron corrosion is to coat the iron with a metal that:
Lorico [155]
  <span>1.)One way to limit iron corrosion is to coat the iron with a metal that: 
A.)will never undergo corrosion 

</span>
3 0
3 years ago
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how many grams of calcium chloride can be prepared from 60.4 G of calcium oxide and 69.0 G of hydrochloric acid and a double dis
Ksenya-84 [330]
Balanced equation: 
<span>CaO + 2 HCl --> CaCl2 + H2O </span>
<span>Calculate moles of each reactant: </span>
<span>60.4 g CaO / 56.08 g/mol = 1.08 mol CaO </span>
<span>69.0 g HCl / 36.46 g/mol = 1.89 mol HCl </span>

<span>Identify the limiting reactant: </span>
<span>Moles CaO needed to react with all HCl: </span>
<span>1.89 mol HCl X (1 mol CaO / 2 mol HCl) = 0.946 mol CaO </span>
<span>Because you have more CaO than that available, HCl is the limiting reactant. </span>

<span>Calculate moles and mass CaCl2: </span>
<span>1.89 mol HCl X (1 mol CaCl2 / 2mol HCl) X 111.0 g/mol = 105 g CaCl2</span>
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3 years ago
I NEED HELP ANSWERING THESE QUESTIONS FOR 50 POINTS!!!!!
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The answers are true, true, false, true, and false.
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