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kherson [118]
3 years ago
14

Alkanes and alkenes differ in that alkene molecules contain at least one:

Chemistry
2 answers:
Karolina [17]3 years ago
7 0

Answer:

The answer to your question is B. double bond.

Explanation:

Both alkanes and alkenes are hydrocarbons composed by carbon and hydrogen.

The different between these compounds is that alkanes have only single bonds are are represented as:         H    H

                                                            |     |

                                                     H - C - C - H

                                                            |      |

                                                           H    H

Alkenes have at least one double bound in their structure and are represented as

         

                                                   H - C = C - H

                                                          |      |

                                                          H    H

Zarrin [17]3 years ago
4 0

Answer:

Double bond

Explanation:

an alkene is a unsaturated hydrocarbon which means that it contain at least one double bond

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Based on solubility, boiling point, and spectroscopic results, a chemist identified an unknown compound as an alcohol. Yet when
mojhsa [17]

Answer:

The compound was a 3° alcohol.

Explanation:

The chromic acid test is positive for 1° and 2° alcohols, but negative for 3° alcohols.

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3 years ago
Imagine that instead of balls, you were rolling positively charged ions of the same element).
Ghella [55]
The ion with a +3 charge would be deflected the most by the magnet because it has the strongest positive charge therefore it will be the one being the most repelled. and the ion that would be deflected the least would be the ion with a +1 charge because it has the least amount of charge so the magnet will still repel it but just not as much as it will repel the ion with a +3 charge.

hope that helps
8 0
2 years ago
in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125
PtichkaEL [24]

Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

3 0
3 years ago
A student uses the periodic table to construct a model that uses a simple diagonal arrow to depict decreasing electronegativity.
Galina-37 [17]

Answer:

helium

Explanation:

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5 0
3 years ago
Enter your answer in the provided box. From the data below, calculate the total heat (in J) needed to convert 0.304 mol of gaseo
diamong [38]

Answer:

-35,281.5 J

Explanation:

To convert the gaseous ethanol to liquid ethanol, three steps will occur. First, it will lose heat and the temperature will decrease until its boiling point, so from 300.0°C to 78.5°C. Thus, more heat will be lost, but now, with the temperature constant, so the gas will be converted to liquid. And then, the liquid will lose heat to decrease the temperature from 78.5°C to 25.0°C.

The total heat loss is the sum of the heats of each step. Because the heat is being removed from the system, it's negative. The first and last step occurs with a change in temperature, and so the heat is calculated by:

Q = m*c*ΔT

Where m is the mass, c is the specific heat of the gas (first step) or liquid (last step), and ΔT the temperature variation (final - initial). The mass of ethanol is the molar mass 46.07 g/mol multiplied by the number of moles, so:

m = 46.07 * 0.304 = 14.00 g

The second step occurs without a change in temperature, and the heat is then:

Q = -n*ΔH°vap

Where n is the number of moles, ΔH°vap is the heat of vaporization, and the minus signal indicates that the heat is being lost. Then, the heat of each step is:

Q1 = 14.00*1.43*(78.5 - 300,0) = -4434.43 J

Q2 = -0.304*40.5 = -12.312 kJ = -12312 J

Q3 = 14.00*2.45*(25.0 - 78.5) = -1835.05 J

Q = Q1 + Q2 + Q3

Q = -35,281.5 J

5 0
3 years ago
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