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kaheart [24]
4 years ago
8

Calculate the percentage composition of (NH4)CO3

Chemistry
2 answers:
ad-work [718]4 years ago
6 0

Answer:

%N = 29.16 %

%H = 8.39 %

%C = 12.50 %

%O = 49.95%

Explanation:

Step 1: Data given

Molar mass of (NH4)2CO3 = 96.086 g/mol

Molar mass of N = 14.007 g/mol

Molar mass of H = 1.008 g/mol

Molar mass of C = 12.011 g/mol

Molar mass of O = 15.999 g/mol

Step 2: Calculate the percentage of the elements

% N = (2*14.007 / 96.086) *100 %

%N = 29.16 %

%H = (8*1.008 / 96.086) *100%

%H = 8.39 %

%C = (12.011 / 96.086) *100%

%C = 12.50 %

%O = (3*15.999/96.086) *100%

%O = 49.95%

faltersainse [42]4 years ago
4 0

Explanation: In order to determine percent composition of the elements in a compound, the molar mass (MM) of each element is divided by the MM of the compound and multiplied by 100. The molar mass of ammonium carbonate ((NH4)2CO3) is 96.086 g/mol .

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mel-nik [20]

Answer: the original volume was 0.98L

Explanation:

V1 =?

T1 = 22k

V2 = 3.8L

T2 = 85k

V1 /T1 = V2 /T2

VI/22 = 3.8/85

V1 = 22 x (3.8/85)

V1 = 0.98L

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Solve the following problem. Give your answer to the correct number of significant figures. a. 20.0 meters x 0012.65 meters b. 0
Nezavi [6.7K]

Explanation:

For multiplication or division, the rule is to count the number of significant figures in each number being multiplied or divided and then limit the significant figures in the answer to the lowest count.

a. 20.0 meters x 0012.65 meters

The numbers are;

20.0 (3 s.f) and 12.65 (4 s.f)

The multiplication gives; 253

Since 253 is already in 3 s.f, that's the answer.

b. 002.5 × 103 meters + 3.50 × 102 meters

The numbers are;

002.5 (2 s.f), 103 (3 s.f), 3.50 (3 s.f) and 102 (3 s.f)

002.5 × 103 = 257.5 = 260 (2 s.f)

3.50 × 102 = 357 = 360 (2 s.f)

260 + 360 = 620

4 0
3 years ago
Consider the equilibrium: HCOOH(aq) + F-(aq) &lt;----&gt; HCOO-(aq) + HF (aq) Given that the Ka of HCOOH = 1.8 x 10-4 and the Ka
Aleks [24]

Hey there!:

K = Ka * Kb / Kw

Ka = 1.8*10⁻⁴

Kb = 10⁻¹⁴ / 6.8*10⁻⁴

K =  1.8*10⁻⁴ * ( 10⁻¹⁴/ 6.8*10⁻⁴ ) * ( 1 / 10⁻¹⁴ )

K =  = 1.8 / 6.8

K = 0.265

Answer A

Therefore:

K is less than on the forward reaction is not favorable .


Hope That helps!

8 0
4 years ago
An uncharged atom of mercury has an atomic number of 80 and an atomic mass of 200. This atom has ________ protons, ________ neut
SCORPION-xisa [38]
<h3>Answer:</h3>

             This atom has 80 protons, 120 neutrons and 80 electrons.

<h3>Explanation:</h3>

Number of Protons:

                               As the number of protons present in the nucleus are equal to the atomic number therefore. As given, the atomic number is 80 therefore, Hg contains 80 protons respectively.

Number of Electrons:

                                 As given in statement, Hg is not carrying any type of charge. It means this atom is neutral in nature. Which means, it is carrying the same number of electrons as the number of protons in order to give a neutral atom. Therefore, it contains 80 electrons.

Number of Neutrons:

                                 Number of neutrons can be calculated using following formula,

                  No. of Neutrons  =  Atomic Mass - Number of Protons

As,

                                    Atomic Mass  =  200

So,

                                    No. of Neutrons  =  200 - 80

                                    No. of Neutrons  =  120

3 0
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