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2 years ago

The Earth revolves around the Sun one year. How many

Mathematics

2 answers:

castortr0y [4]2 years ago

7 0

Answer:

Weeks = 52

Days = 365

Hours = 8,760

Minutes = 525,600

Seconds = 3.1536 × 10^7

Step-by-step explanation:

Tanya [424]2 years ago

3 0

Answer:

1 Year =

31540000 seconds.

525600 minutes.

8760 hours.

365 days.

52.1429 weeks.

12 months.

Step-by-step explanation:

Hey there!

You can do this by calculating all the numbers since you already know that there are 24 hours in a day, 12 months in a year and 365 days in a year

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Determine the value of x for the following equations.

mafiozo [28]

Answer:

I'm so sorry!!! I don't understand how you are supposed to do this problem... I hope someone can help you out. Have a good day

Step-by-step explanation:

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4 0

3 years ago

5A+10=200. Solve the problem

USPshnik [31]

Answer: A = 38

Steps:
5A = 200 - 10
5A = 190
A = 190/5
A = 38

I hope this helps :)

5 0

3 years ago

Read 2 more answers

What is the complete factorization of the polynomial function over the set of complex numbers?

quester [9]

Answer:

f(x)=(x-2)(x+2)(x-5)

Step-by-step explanation:

f(x)=x³-5x²+4x-20 1. Just group randomly

f(x)=x²(x-5)+4(x-5) 2. Factor the groupings

f(x)=(x²+4)(x-5)

<u>f(x)=(x-2)(x+2)(x-5)</u> 3. Factor the difference of two squares

6 0

4 years ago

Read 2 more answers

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

HELP! I’ll MARK BRAINLIEST

Grace [21]

Answer:

they ran 5 and 2 and half hour

Step-by-step explanation:

they ran 5 and 2 and half hour

6 0

3 years ago