H2(g) +C2H4(g)→C2H6(g)
H-H +H2C =CH2→H3C-Ch3
2C -H bonds and one C-C bond are formed while enthalpy change (dH) of the reaction,
H-H: 432kJ/mol
C=C: 614kJ/mol
C-C: 413 kJ/mol
C-C: 347 kJ/mol
dH is equal to sum of the energies released during the formation of new bonds or negative sign, and sum of energies required to break old bonds or positive sign.
The bond which breaks energy is positive.
432+614 =1046kJ/mol
Formation of bond energy is negative
2(413) + 347 = 1173 kJ/mol
dH reaction is -1173 + 1046 =-127kJ/mol
Answer:
a.
Explanation:
At 28 degrees highest line is CaCl2. Answer a.
Answer:
Assuming it was collected from the atmosphere it would be virtually nothing
Explanation:
hydrogen makes up 0.000055% of the atmosphere while oxygen makes up 23 percent. 20/400000 cm^3 of hydrogen
Atomic number of O= 8
Atomic number of F = 9
Electron configurations:
⁸O = 1s² 2s² 2p⁴
⁹F = 1s² 2s² 2p⁵
Total electrons: 8+ 9 = 17
For OF the molecular electron configuration would be:
OF = (1σ)²(1σ*)²(2σ)²(2σ*)²(2pσ)²(2pπ)⁴(2pπ*)³
OF⁺ suggests a loss of one electron from the 2pπ* orbital leaving the configuration as:
OF⁺ = (1σ)²(1σ*)²(2σ)²(2σ*)²(2pσ)²(2pπ)⁴(2pπ*)²
Thus, based on MO theory there are two unpaired electrons in OF⁺ ion
