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larisa [96]
3 years ago
15

How many elements are in one molecule of Methane?

Chemistry
1 answer:
Sedbober [7]3 years ago
4 0
3 elements are in one chemical
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How many grams of cobalt (II) nitrate, Co(NO3)2, are required to make a 2.20%(w/v) aqueous solution in a 250 mL volumetric flask
shutvik [7]

Answer:

\large \boxed{\text{5.50 g}}

Explanation:

Percent means " per hundred," so % m/V means the grams of something in 100 mL of  volume.

\text{m/V \%} = \dfrac{\text{mass of solute} }{\text{volume of solution}} \times 100 \, \%

Data:

         m/V % = 2.20 %

V of solution = 250 mL

Calculations:

\text{2.20 \%} = \dfrac{\text{mass of solute} }{\text{250 mL}} \times 100 \, \%\\\\\text{Mass of solute} = \dfrac{2.20\, \% \times \text{250 mL}}{100 \%} = \text{5.50 g}\\\\\text{The mass of Co(NO$_{3}$)$_{2}$ is $\large \boxed{\textbf{5.50 g}}$}

8 0
3 years ago
Near a volcano you would find?
Genrish500 [490]

Answer: Could you be more specific?

5 0
3 years ago
4. Suppose you want to deposit silver on an iron spoon using silver nitrate as
Levart [38]

The spoon should be connected to the negative terminal of the battery. The other electrode should be made of silver.

8 0
2 years ago
Based on the following equation, how many moles of hydrochloric acid (HCl)are needed to react with 0.44 moles of potassium
inysia [295]

Answer:

1.76 moles of HCl.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KMnO₄ + 8HCl —> 3Cl₂ + 2MnO₂ + 4H₂O + 2KCl

From the balanced equation above,

2 moles of KMnO₄ reacted with 8 moles of HCl.

Finally, we shall determine the number of mole of HCl needed to react with 0.44 moles of KMnO₄. This can be obtained as follow:

From the balanced equation above,

2 moles of KMnO₄ reacted with 8 moles of HCl.

Therefore, 0.44 moles of KMnO₄ will react with = (0.44 × 8)/2 = 1.76 moles of HCl.

Thus, 1.76 moles of HCl is needed for the reaction.

5 0
3 years ago
Suppose 3.68g of zinc was allowed to react with hydrochloric acid to produce zinc chloride and hydrogen gas. How much zinc chlor
valentina_108 [34]

Answer:

Percent yield = 86.2%

Explanation:

Given data:

Mass of zinc = 3.68 g

Mass of zinc chloride = ?

Percent yield = ?

Actual yield = 7.12 g

Solution:

Chemical equation:

Zn + 2HCl  → ZnCl₂  + H₂

Number of moles of zinc:

Number of moles  = Mass /molar mass

Number of moles = 3.68 g / 65.38 g/mol

Number of moles  = 0.06 mol

Now we will compare the moles of ZnCl₂ with zinc.

                 Zn            :               ZnCl₂

                  1               :               1

                 0.06           :            0.06

Theoretical yield of zinc chloride:        

Mass of ZnCl₂ = moles × molar mass

Mass of ZnCl₂ = 0.06 mol × 136.286 g/mol

Mass of ZnCl₂ =  8.2 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 7.12 g/ 8.2 g × 100

Percent yield = 86.2%

7 0
4 years ago
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