We know that

ρ = density of gasoline = 737 kg/m³ (at T = 60°F = 15.6°C)
ρ = m/V
ρV = m
V = m/ρ
V = 49.0 kg / 737 kg/m³
V = 0.066 m³

[volume of the tank]=L*W*H-----> H=volume/[L*W]----> H=0.066/(0.9*0.4)
H=0.1833 m

the answer is
the depth of the tank is 0.18 m

5 0

3 years ago

There are 23 classes in the fourth grade. Each grade has 21 students. Write a number sentence that will provide a reasonable est

lapo4ka [179]

23 can round to 20 and 21 can also round to 20 so all u do is 20x20=400 so 400 is your estimated answer

6 0

3 years ago

Holly is taking out a loan in the amount of $10,000. Her choices for the loan are a 4-year loan at 4% simple interest and a 6-ye

notsponge [240]

Answer:

The difference in the amount of interest she would have to pay for the two loans is $1,400

Step-by-step explanation:

The amount of loan Holly is taking out, P = $10,000

The choices available for the loan are;

1) Loan duration, T₁ = 4-year

Interest rate, R₁ = 4%

2) Loan duration, T₂ = 6-year

Interest rate, R₂ = 5%

For the first choice, we have;

The simple interest, I, given by the formula;

$I_1 = \dfrac{P \times R_1 \times T_1 }{100} = \dfrac{10,000 \times 4 \times 4 }{100} = \$ 1,600$

For the second choice, we have;

The simple interest, I, given by the formula;

$I_2 = \dfrac{P \times R_2 \times T_2 }{100} = \dfrac{10,000 \times 5 \times 6 }{100} = \$ 3,000$

The difference, D, in the amount of interest she would have to pay for the two loans is therefore;

D = I₂ - I₁ = $3,000 - $1,600 = $1,400

The difference in the amount of interest she would have to pay for the two loans = D = $1,400.

7 0

3 years ago

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