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Marina86 [1]
1 year ago
15

If a 2 meter diameter ball representing the Sun were placed in Center Circle in Indianapolis, how far away should the Earth be p

laced?
Physics
1 answer:
fgiga [73]1 year ago
6 0

By applying the correspondent change of scale, we will see that Earth should be placed 214.8m away from the scale sun.

<h3></h3><h3>How far the Earth should be placed?</h3>

The real radius of the Sun is:

R = 696,340 km

And the radius of the scale Sun is 1m, then we have the relation:

1m = 696,340 km

1 = (1m/696,340 km)

Now, the real distance between the Sun and Earth is:

d = 149,600,000 km

If we apply the change of scale we have above, we will get:

d =  149,600,000 km*(1m/696,340 km) = 214.8m

So the Earth should be placed at 214.8m of the ball that represents the sun.

If you want to learn more about changes of scale, you can read:

brainly.com/question/15891755

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What special day is when Massachusetts receives the most indirect rays of the sun?
viva [34]

In December solstice Massachusetts receives the most indirect rays of the sun. It happened on the day of 21st of December.

<u>Explanation</u>:

Winter solstice festivities bring "stillness, light, and warmth" into this period of the occasion hustle. Keeping that in mind, we give you this gathering of mysterious occasions to stamp the day of the year (this year, Friday, December 21) with the briefest time of sunlight and the longest night of year. Also, obviously, to respect the arrival of the sun and the more extended days to come.

6 0
2 years ago
A man attempts to pick up his suitcase of weight ws by pulling straight up on the handle. (See Figure 1) However, he is unable t
cupoosta [38]

Answer:

Normal force, N = W_s - F

Explanation:

Let w_s is the weight of suitcase. A man attempts to pick up his suitcase by pulling straight up on the handle. The weight of the suitcase in downward direction. The normal force is acting in upward direction. Let F is the force with which it is pulled straight up.

So, the normal force is given by :

N = W_s - F

N = mg - F

mg is the weight of the suitcase.

Hence, this is the required solution.

3 0
3 years ago
A 2000 Kg car going 20 m/s crashes into a wall. What is the force of the car on the wall? ​
lidiya [134]

Answer:

40,000N

Explanation:

Force = Acceleration × Mass

2000×20=40,000

4 0
3 years ago
What is the difference between p-n junction diode and extrinsic semiconductor?
Anna71 [15]

Answer:

The difference between P-N junction diode and extrinsic semiconductor is the allowable direction of flow of current

The extrinsic semiconductor can allow current to flow in both directions while the P-N junction diode permits only a unidirectional flow of current

Explanation:

A semiconductor is a substance that has an intermediate conductivity between that of conductors and non conductors

Examples of semiconductors  include germanium and cadmium selenide

A semiconductor to which impurities has been added (an activity known as doping) is an extrinsic semiconductor

Based on the functioning of a semiconductor, doping result in the formation of one of two types of semiconductors including;

1) N-type semiconductor that has an extra electron and the charge carriers are electrons

2) P-type semiconductor that has one less (-e⁻) electron and holes are the charge carriers

An extrinsic semiconductor can conduct allow the flow of electricity in both ways

A P-N junction diode consists of both the P and N-type extrinsic semiconductors arranged such that current can flow in only one direction.

Therefore, the difference is that the extrinsic semiconductor can allow current flow in both directions while the P-N junction diode permits only a unidirectional flow of current.

4 0
3 years ago
A jetliner rolls down the runway with constant acceleration from rest, it reaches its take off speed of 250 km/h in 1 min. What
nlexa [21]

Answer:

Acceleration, a=14970.05\ km/h^2

Explanation:

Given that,

Initially, the jetliner is at rest, u = 0

Final speed of the jetliner, v = 250 km/h

Time taken, t = 1 min = 0.0167 h

We need to find the acceleration of the jetliner. The mathematical expression for the acceleration is given by :

a=\dfrac{v-u}{t}

a=\dfrac{250}{0.0167}

a=14970.05\ km/h^2

So, the acceleration of the jetliner is 14970.05\ km/h^2. Hence, this is the required solution.

3 0
3 years ago
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