All categories

3 years ago

Difference between reproducibility and replicability

1 answer:

8 0

Suppose you are doing an experiment where you determine the value of one parameter, say density of a liquid. You have two methods in doing this. By finding the mass and volume, and by using a densitometer. Reproducibility is when you get the same value of density for both methods. Replicability is when you have similar results in one method. So, replicability is a measure of precision, while reproducibility is a measure of accuracy.

You might be interested in

And event or situation that causes a strain on your body or mind is called a help asap

faltersainse [42]

I'm quite certain the answer is "stress".

7 0

3 years ago

The compound ethylene (C2H4) is represented by this diagram. What statement best describes the arrangement of the atoms in an et

Effectus [21]

Answer: The correct answer is two electrons are shared between each hydrogen atom and the carbon atom bonded to it, and four electrons are shared between the carbon atoms.

Explanation:

Ethylene is a compound given by the chemical formula $H_2C=CH_2$ .

The bond present between hydrogen and carbon atoms or carbon and carbon atoms are covalent bonds. A covalent bond is formed by the sharing of electrons between the atoms combining.

A double bond is present between carbon and carbon atoms. So 2 pairs of electrons are shared which means in total of 4 electrons are shared.

Bond present between hydrogen and carbon atoms are single bonds. So, a pair of electrons is shared which means that in total of 2 electrons are shared.

Hence, the correct answer is two electrons are shared between each hydrogen atom and the carbon atom bonded to it, and four electrons are shared between the carbon atoms.

6 0

3 years ago

Read 2 more answers

A 34.00 kg sample of mud has a specific heat of 2,512 J/kg °C.

Elena-2011 [213]

Answer:

B ig lol

Explanation:

6 0

3 years ago

If two opposite charges get farther apart, does their attraction for each other increase, decrease, or remain the same?

wlad13 [49]

The force between them decreases, as the square of the distance.

For example ...

-- If you move them apart to double the original distance, the force becomes (1/2²) = 1/4 of the original force.

-- If you move them apart to 3 times the original distance, the force becomes (1/3²) = 1/9 of the original force.

-- If you move them apart to 5 times the original distance, the force becomes (1/5²) = 1/25 of the original force.

(Gravity works exactly the same way.)

7 0

3 years ago

A 6.72 particle moves through a region of space where an electric field of magnitude 1270 N/C points in the positive direction,

Romashka [77]

Answer:

$v_{y} = -104 m/s$

Explanation:

Using:

Force = electric field * charge

$F=e*q$

Force = magnitude of charge * velocity * magnetic field * sin tither

$F_{x2}= |q|*v*B*sin \alpha$

Force on particle due to electric field:

$F_{x1}= E*q = (1270N/C)*(-6.72*10^{-6} ) = -8.53*10^{-3}$

Force on particle due to magnetic field:

$F_{x2}= |q|*v*B*sin \alpha = (6.72*10^{-6} )*(1.15)*(sin90)*v = (7.728*10^{-6})*(v)$

$F_{x2}$ is in the positive x direction as $F_{x1}$ is in the negative x direction while net force is in the positive x direction.

Magnetic field is in the positive Z direction, net force is in the positive x direction.

According to right hand rule, Force acting on particle is perpendicular to the direction of magnetic field and velocity of particle. This would mean the force is along the y-axis. As this is a negatively charged particle, the direction of the velocity of the particle is reversed. Therefore velocity of particle, v, has to be in the negative y direction.

Now,

$F_{xnet}- F_{x1 } = F_{x2 }$

$(6.13*10^{-3}) - (8.53*10^{-3} ) = (7.728*10^{-6})*(v)$

$v = (F_{xnet} - F_{x1}) / (F_{x2} )$

$=((6.13*10^{-3} ) - (8.53*10^{-3})) / (7.728*10^{-6})$

$= (- 104.25) m/s$

$v_{y} = -104 m/s$

8 0

3 years ago