Vertex is (-5,-10) y intercept of g is (0,-1) zeroes of h are x=-3,1
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
Answer:
GH = 9
Step-by-step explanation:
FH=FG+GH
21= 12+GH
GH = 21-12 =9
I hope I helped you^_^
Answer:
13.7142857143
Step-by-step explanation:
If you need to round then do so, or i will comment the rounded version if needed.
Answer:
No
Step-by-step explanation:
In this particular scenario, based on the numbers I would say that it does not make sense to represent this with a constant rate. That is because in a span of three years the change between each year is completely different, for example, between the first and second year there was a change of
9.75 - 8.50 = 1.25 dollar change
1.25 / 8.50 = 0.147 or a 14.7% increase
Between the second and third year, there was a change of
12 - 9.75 = 2.25 dollar change
2.25 / 9.75 = 0.23 or 23% increase
Therefore, each year the percent and dollar value increase is increasing more and more which would not be a constant rate.
