In how many years will 600$ double itself at 10% simple interest?

Mathematics

2 answers:

Harlamova29_29 [7]2 years ago

6 0

Answer:

10years

Step-by-step explanation:

100%+100%=double

100/10=10 years to reach 100% so after ten years you will have 200%/double

cestrela7 [59]2 years ago

4 0

$\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\ \\$

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P (Principal) → 600$
R (the annual rate) → 10% ,0.1

Time → years let be x

$\sf{A = 2P} \\ \sf{A = 2 \times 600} \\ \sf{ A =\:1200} \\ \sf{cuz \: future \: value \: since \: the \: 600 \: will \: double \: itself}$

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$\\ \large \purple { \sf{Formula \: used→}} \\ \\ \rm{A = P(1 + r \times t)}$

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→Substituting values

$\rm{1200 = 600(1 + 0.1 \times x)} \\ \\ \rm{600(1 + 0.1 \times x) = 1200} \\ \\ \rm{1 + 0.1 \times x = \frac{1200}{600} } \\ \\ \rm{ 1 + 0.1 \times x = \cancel \frac{1200}{600} } \\ \\ \rm{1 + 0.1 \times x = 2} \\ \\ \rm{0.1 \times x = 2 - 1} \\ \\ \rm{x = 1 \times \frac{10}{1} } \\ \\ \rm{x =10 }$