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Stels [109]
2 years ago
15

In how many years will 600$ double itself at 10% simple interest?​

Mathematics
2 answers:
Harlamova29_29 [7]2 years ago
6 0

Answer:

10years

Step-by-step explanation:

100%+100%=double

100/10=10 years to reach 100% so after ten years you will have 200%/double

cestrela7 [59]2 years ago
4 0

\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\  \\

\\  \large \purple{ \sf{Given→}} \\

  • P (Principal) → 600$
  • R (the annual rate) → 10% ,0.1

nd

  • Time → years let be x

\sf{A = 2P}  \\ \sf{A =  2 \times 600}  \\ \sf{  A =\:1200}  \\  \sf{cuz \:  future  \: value \:  since \:  the  \: 600  \: will  \: double  \: itself}

\blue{\rule{70mm}{2.2pt}}

\\  \large \purple { \sf{Formula  \: used→}} \\   \\  \rm{A = P(1 + r \times t)}

\blue{\rule{70mm}{2.2pt}}

→Substituting values

\rm{1200  = 600(1 + 0.1 \times  x)} \\  \\  \rm{600(1 + 0.1 \times x) = 1200} \\  \\   \rm{1 + 0.1  \times  x =  \frac{1200}{600} } \\  \\ \rm{ 1 + 0.1 \times x =  \cancel  \frac{1200}{600} } \\  \\  \rm{1 + 0.1 \times  x = 2} \\  \\  \rm{0.1  \times  x = 2 - 1} \\  \\  \rm{x = 1 \times  \frac{10}{1} }  \\  \\  \rm{x =10 }

\underline{\underline{\rule{70mm}{2.2pt}}}\sf{\:мѕнαcкεя\: ♪...}

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