3 years ago

Write a two-column proof on a space provided

Mathematics

1 answer:

Gnom [1K]3 years ago

4 0

Answer:

Step-by-step explanation:

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I think the answer should be 12 but......

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C and E

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3 years ago

25x^-4-99x^-2-4=0 <br> How do I solve for this?

OlgaM077 [116]

Given

$25x^{-4} - 99x^{-2} - 4 = 0$

consider substituting $y=x^{-2}$ to get a proper quadratic equation,

$25y^2 - 99y - 4 = 0$

Solve for $y$ ; we can factorize to get

$(25y + 1) (y - 4) = 0$

$25y+1 = 0 \text{ or } y - 4 = 0$

$y = -\dfrac1{25} \text{ or }y = 4$

Solve for $x$ :

$x^{-2} = -\dfrac1{25} \text{ or }x^{-2} = 4$

The first equation has no real solution, since $x^{-2} = \frac1{x^2} > 0$ for all non-zero $x$ . Proceeding with the second equation, we get

$x^{-2} = 4 \implies x^2 = \dfrac14 \implies x = \pm\sqrt{\dfrac14} = \boxed{\pm \dfrac12}$

If we want to find all complex solutions, we take $i=\sqrt{-1}$ so that the first equation above would have led us to

$x^{-2} = -\dfrac1{25} \implies x^2 = -25 \implies x = \pm\sqrt{-25} = \pm5i$

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2 years ago

You and two friends got jobs at stores in the mall. You earn $117.60$117.60 for 1414 hours of work. Ty earns $148.50$148.50 in 1

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highest pay rate is Kim

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