I believe it would be 7.731. x 10^5? That is if they want you to evaluate.
LIKE DISSOLVES LIKE. Since Ccl4 is non-polar, it'll be soluble in any non-polar solvent. Hope this helps you!
This question is based in mole ratios. for every mole of cl2, 2 moles of NaCl will be produced. so half of the moles of NaCl gives the moles of Cl2 required. therefore divide 0.35 by 2
5-chloro-2-pentyne. The chain must be numbered starting with the end nearest the triple bond.
