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jarptica [38.1K]
2 years ago
10

11. Trait theory claims that

Physics
1 answer:
svetoff [14.1K]2 years ago
3 0
A. people from the same location share the same personality type.
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What is the current I(3τ), that is, the current after three time constants have passed? The current in the circuit will approach
Olin [163]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

I(\tau)=0.051 A

b

I(3 \tau)=0.076 A

c

I_c= 0.08 A

Explanation:

From the question we are told that

                I(t) = \frac{e}{R}(1-e^{\frac{t}{\tau} }) ; \ Where \ \tau = L/R

From the question we are told to find I(\tau) when t=0  equals the time constant (\tau)

That is to obtain I(\tau).This  is mathematically represented as

                   I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{\tau}{\tau} })

             Substituting 12 V for \epsilon and 150Ω for R

                     I(\tau) = \frac{12}{150} (1- e^{-1})

                            =0.051 A

From the question we are told to find I(3 \tau) when t=0  equals the 3 times the  time constant (\tau)

That is to obtain I(3\tau).This  is mathematically represented as

                 I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{3\tau}{\tau} })

                  I(\tau) = \frac{12}{150} (1- e^{-3})

                        =0.076 A

As tends to infinity \frac{\infty}{\tau}  = \infty

So I_c would be mathematically evaluated as

               I_c=I(\infty) = \frac{12}{150} (1- e^{- \infty})

                   = \frac{12}{150}

                   = 0.08 A

5 0
3 years ago
Law of conservation<br> of momentum
ikadub [295]

Answer:

Explanation:

Law of conservation of momentum is applied in solving collision problem. When two body collides, their momentum after collision can be determined using the law.

The law States that the sum of momentum of two bodies before collision is equal to the sum of their momentum after collision. Before collision, both bodies moves with a different velocity while during some cases, the bodies moves with a common velocity after collision.

Whether they move with or without the same velocity depends on the type of collision that exists between them after the collision. After collision, some object sticks together and move with a common velocity while some doesn't.

If the bodies sticks together after collision, the type of collision that occur is inelastic (energy is not conserved) and if they splits after collision, the type of collision that occur is an elastic collision (energy is conserved).

Let m1 and m2 be the masses of the bodies

u1 and u2 be their velocities before collision

v1 and v2 be their velocities after collision.

According to the law;

m1u1 + m2u2 = m1v1 + m2v2

Note that momentum = mass × velocity of the body.

5 0
3 years ago
6. The hole on a level, elevated golf green is a horizontal distance of 150 m from the tee and at an elevation of 12.4 m above t
Georgia [21]

Answer:

u = 104.68 m/s

Explanation:

given,

horizontal distance = 150 m

elevation of  12.4 m

angle = 8.6°

horizontal motion = x = u cos θ. t .............(1)

vertical motion =

y = u sin \theta - \dfrac{1}{2}gt^2................(2)

from equation(1) and (2)

y = x tan \theta - \dfrac{gx^2}{2u^2cos^2\theta}..........{3}

12.4 = 150\times tan (8.6) - \dfrac{9.8\times 150^2}{2u^2cos^2(8.6)}

\dfrac{9.8\times 150^2}{2u^2cos^2(8.6)} = 10.29

\dfrac{9.8\times 150^2}{2\times 10.29\times cos^2(8.6)} = u^2

u = \sqrt{10959.34}

u = 104.68 m/s

The initial speed of the ball is u = 104.68 m/s

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