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Mashutka [201]
3 years ago
14

Which of the following correctly shows the four most abundant gases in the Earth's atmosphere in order from most abundant to lea

st abundant?
A.
oxygen, nitrogen, argon, carbon dioxide
B.
nitrogen, oxygen, argon, carbon dioxide
C.
oxygen, nitrogen, carbon dioxide, argon
D.
nitrogen, oxygen, carbon dioxide, argon
Physics
2 answers:
AURORKA [14]3 years ago
5 0

Answer:

B is the answer

Explanation:

ASHA 777 [7]3 years ago
3 0

The correct answer is

B. nitrogen, oxygen, argon, carbon dioxide


In fact, the abundance of the gases in the earth's atmosphere is as follows:

1) Nitrogen: 78.0 %

2) Oxygen: 21.0 %

3) Argon: 0.9 %

4) Carbon dioxide: < 0.1 %

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Carbon will become positively charged.

The charge of Carbon will be +4.

Explanation:

The charge of Carbon will be +4.

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This will make carbon have a charge of +4

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If it has enough kinetic energy, a molecule at the surface of the Earth can "escape the Earth's gravitation", in the sense that
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Answer:

K_E=mgr_E

Explanation:

By conservation of energy, the sum of the kinetic and gravitational potential energies at the surface of the Earth must be equal than their sum at infinity, so we have:

K_E+U_E=K_\infty+U_\infty

\frac{mv_E^2}{2}-\frac{GM_Em}{r_E}=\frac{mv_\infty^2}{2}-\frac{GM_Em}{r_\infty}

Where G=6.67\times10^{-11}Nm^2/kg^2 is the gravitational constant,M_E=5.97\times10^{24}kg and r_E=6371000m are the mass and radius of the Earth, <em>m </em>is the mass of the particle, v_E its velocity at the surface of the Earth (which would be its escape velocity) and v_\infty and r_\infty are the velocities and distance at infinity, which would be null and infinity respectively, so the right hand side of our equation is 0J, which leaves us with:

\frac{GM_Em}{r_E}=\frac{mv_E^2}{2}=K_E

Also, since the force the molecule experiments is the force of gravity (disregarding drag), we can write its weight in terms of Newton's Law of Gravitation:

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Which means that:

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So finally putting all together we can write:

K_E=\frac{GM_Em}{r_E}=mgr_E

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