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2 years ago

A valid lewis structure of __________ cannot be drawn without the central atom violating the octet rule. pf5 pcl3 so3 ccl4 co2

Chemistry

1 answer:

lakkis [162]2 years ago

8 0

The answer will be, so3 since s only need two electrons to complete its octet

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Please help, please don’t answer links

lakkis [162]

Answer:

0.093 mole of C₆H₁₂.

Explanation:

We'll begin by calculating the molar mass of C₆H₁₂. This can be obtained as follow:

Molar mass of C₆H₁₂ = (12×6) + (12×1)

= 72 + 12

= 84 g/mol

Finally, we shall determine the number of mole in 7.8 g of C₆H₁₂. This can be obtained as follow:

Molar mass of C₆H₁₂ = 84 g/mol

Mass of C₆H₁₂ = 7.8 g

Mole of C₆H₁₂ =?

Mole = mass / molar mass

Mole of C₆H₁₂ = 7.8 / 84

Mole of C₆H₁₂ = 0.093 mole

Thus, 7.8 g contains 0.093 mole of C₆H₁₂.

3 0

2 years ago

A soccer balll is travelling at a velcrocity of 50ms the kinetic energy of the ball is 500 what is the mass of the soccer ball

Verizon [17]

KE = mv²/2

m=2*KE/v²

v=50 m/s

KE=500J

m=2*KE/v² =2*500/50²=1000/2500= 0.4 kg

3 0

3 years ago

In order to draw a conclusion, scientists must_______ data from an investigation

Alenkinab [10]

The answer is record

6 0

3 years ago

Of the following metals, which is the LEAST reactive? <br> A. K<br> B. Ca<br> C. Na<br> D. Mg

emmainna [20.7K]

The Answer Should Be D.Mg

6 0

2 years ago

Read 2 more answers

3. Crystalline structural unit of barium metal is a body-centered cubic cell. The edge length of the unit cell is 5.02x10-8 cm.

tiny-mole [99]

Answer:

The Avogadro's number is $N_A = 6.02289 *10^{23}$

Explanation:

From the question we are told that

The edge length is $L = 5.02 * 10^{-8} \ cm= \frac{5.02 * 10^{-8} }{100} = 5.02 * 10^{-10}$

The density of the metal is $\rho = 5.30\ g/cm^3 = 5.30 * \frac{g}{cm^3} * \frac{1*10^6}{1*10^3} = 5.30 *10^3kg/m^3$

The molar mass of Ba is $Z = 137.3 \ g/mol = \frac{137.3}{1000} = 0.1373 \ kg / mol$

Generally the volume of a unit cell is

$V = L^3$

substituting value

$V = [5.02 *10^{-10}]^3$

$V = 1.265*10^{-28}\ m^3$

From the question we are told that 68% of the unit cell is occupied by Ba atoms and that the structure is a metal which implies that the crystalline structure will be (BCC),

The volume of barium atom is

$V_a = \frac{V}{2} * 0.68$

substituting value

$V_a = \frac{ 1.265*10^{-28}}{2} * 0.68$

$V_a = 4.301 *10^{-29} \ m^3$

The Molar mass of barium is mathematically represented as

$Z = N_A V_a * \rho$

Where $N_A$ is the Avogadro's number

$N_A = \frac{ Z}{ V_a * \rho}$

substituting value

$N_A = \frac{ 0.1373}{ 4.301*10^{-29} * 5.3*10^{3}}$

$N_A = 6.02289 *10^{23}$

4 0

2 years ago