Answer:
B
Explanation:
962,320 J
230 nutritional Calories in Joules is 962,320 J
<h3>
Answer:</h3>
C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)
<h3>
Explanation:</h3>
The balanced chemical equation for the combustion of the hydrocarbon in question is;
C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)
- A balanced chemical equation is one in which the number of atoms of each element is equal on both sides of the equation.
- Reactant side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms
- Product side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms
- An equation is balanced by putting appropriate coefficients on reactants and products involved in the reaction.
- An equation is balanced so as to obey the law of conservation of mass.
The one that is being described above is what we call SCIENTIFIC LAW. Scientific law is what explains of what will happen every time in a certain situation. This is also different from scientific theory since scientific theory only gives an explanation to a group of happenings and this can still be modified. Hope this helps.
It is important for scientists and engineers to be able to control the design of the material because<u> it create solutions to problems</u>.
<h3>Why material science and engineering is important?</h3>
What things are made of and why they behave the way they do are lessons we learn from materials science. Materials engineering teaches us how to use knowledge to improve things and the way they are made. Research and industry innovation in fields as diverse as aerospace and medicine are driven by materials science and engineering.
<h3>Why is it important for scientists to use the scientific method?</h3>
The scientific method is essential because: It follows a set of rules. Scientists conduct experiments in a standardized manner because the steps used in the scientific method are systematic. This suggests that their research might be spread widely.
To know more about aerospace :
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You must add 7.5 pt of the 30 % sugar to the 5 % sugar to get a 20 % solution.
You can use a modified dilution formula to calculate the volume of 30 % sugar.
<em>V</em>_1×<em>C</em>_1 + <em>V</em>_2×<em>C</em>_2 = <em>V</em>_3×<em>C</em>_3
Let the volume of 30 % sugar = <em>x</em> pt. Then the volume of the final 20 % sugar = (5 + <em>x</em> ) pt
(<em>x</em> pt×30 % sugar) + (5 pt×5 % sugar) = (<em>x</em> + 5) pt × 20 % sugar
30<em>x</em> + 25 = 20x + 100
10<em>x</em> = 75
<em>x</em> = 75/10 = 7.5
