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Nina [5.8K]
4 years ago
15

20 points if you solve these please last project then i'm done with school

Chemistry
2 answers:
Mariana [72]4 years ago
8 0
Number three is around 40 points.
I hoped this helped.
kirill115 [55]4 years ago
3 0
You will get about 40 moles
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The product of nuclear ___ is several nuclei
garri49 [273]

I think Its "fission"

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3 years ago
What would be the effect on the calculated ratio (mole of copper:mole of iron) if:
kotegsom [21]

Explanation:

Since the ratio is Cu/Fe, if some Fe were lost due to spillage, the Cu/Fe ratio would INCREASE because Fe would be lower.

5 0
3 years ago
For each property listed, identify the type of element it describes.
Juliette [100K]

Answer:

1.Very good electrical conductivity :<u> Metals</u> (Decreacing order of conductivity)

  • <em>Silver > Copper > Gold > aluminium</em>

2. Amphoteric <u>: Metal elements</u>

  • <em>Beryllium , Aluminium , Zinc </em>,

3.Gaseous at room temperature: mostly <u>Nobel gases elements</u> and some non - metal elements.

  • <em>Helium ,neon , argon , krypton , fluorine , Oxygen , nitrogen</em>

4.Solid at room temperature:<u> Mostly Metals</u> (few non-metals, metalloid elements)

  • <em>Metals (Sodium  , potassium , calcium , gold are solid)</em>

<em>Non- metals(Carbon ,Boron )</em>

<em>Metalloids(antimony)</em>

<em>5.</em> Brittle <em>: </em><u>non - metals </u>(can't be rolled into wires)

<em>Hydrogen , carbon , sulfur , phosphorus</em><u> </u>

Explanation:

6 0
3 years ago
Read 2 more answers
How many moles of atoms are contained in 15.7 g of Bromine
Vlada [557]
1 mol of Br = 79.9 g

15.7 g / 79.9 g = 0.196 moles of atoms
3 0
4 years ago
What is the half life of the element in the picture<br><br> HELP BRAINLIEST
stira [4]

Answer:

6 days

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 100 mg

Amount remaining (N) = 6. 25 mg

Time (t) = 24 days

Half life (t½) =?

Next, we shall determine the decay constant. This can be obtained as follow:

Original amount (N₀) = 100 mg

Amount remaining (N) = 6. 25 mg

Time (t) = 24 days

Decay constant (K) =?

Log (N₀/N) = kt / 2.303

Log (100/6.25) = k × 24 / 2.303

Log 16 = k × 24 / 2.303

1.2041 = k × 24 / 2.303

Cross multiply

k × 24 = 1.2041 × 2.303

Divide both side by 24

K = (1.2041 × 2.303) / 24

K = 0.1155 /day

Finally, we shall determine the half-life of the isotope as follow:

Decay constant (K) = 0.1155 /day

Half life (t½) =?

t½ = 0.693 / K

t½ = 0.693 / 0.1155

t½ = 6 days

Therefore, the half-life of the isotope is 6 days

5 0
3 years ago
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