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3 years ago

The name of Earth's single, huge continent from over 250 million years ago is (1 point)

Chemistry

2 answers:

babunello [35]3 years ago

5 0

The answer is pangea.

pochemuha3 years ago

3 0

B. Pangaea or Pangaea Ulitma

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Which is an example of a homogeneous mixture?

goldenfox [79]

Answer:

Clean Air So B

Explanation:

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3 years ago

2 The substance has a mass of 0.50 kg.

katen-ka-za [31]

Answer:

68000J/kg

Explanation:

Given parameters:

Mass of the substance = 0.5kg

Quantity of heat transferred to the body = 34000J

Unknown:

Specific latent heat of fusion = ?

Solution:

The specific latent heat is usually involve in phase changes;

H = mL

H is the quantity of heat supplied

m is the mass

L is the specific latent heat

Insert the parameters and solve;

34000 = 0.5 x L

L = $\frac{34000}{0.5}$ = 68000J/kg

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3 years ago

Suppose that magnesium would react exactly the same as copper in this experiment. how many grams of magnesium would have been us

Vikentia [17]

The solution for this problem would be:

We are looking for the grams of magnesium that would have been used in the reaction if one gram of silver were created. The computation would be:

1 g Ag (1 mol Mg) (24.31 g/mol) / (2mol Ag)(107.87g/mol) = 0.1127 grams of Magnesium

6 0

3 years ago

A certain flexible weather balloon contains 3.5 L of helium gas. Initially, the balloon is in WP at 8500ft, where the temperatur

Advocard [28]

Answer:

$\large \boxed{\text{3.9 L}}$

Explanation:

We can use the Combined Gas Laws to solve this problem

$\dfrac{p_{1}V_{1} }{T_{1}} = \dfrac{p_{2}V_{2}}{T_{2}}$

Data

p₁ = 571.2 Torr; p₂ = 400 Torr

V₁ = 3.5 L; V₂ = ?

T₁ = 21.5 °C; T₂ = 6.8 °C

Calculations

(a) Convert the temperatures to kelvins

T₁ = (21.55 + 273.15) K = 294.70 K

T₂ = (6.8 + 273.15) K = 279.95 K

(b) Calculate the new volume

$\begin{array}{rcl}\dfrac{p_{1}V_{1} }{T_{1}} & = & \dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{\text{571.2 Torr $\times$ 3.5 L}}{\text{294.65 K}} & = & \dfrac{\text{400 Torr} \times V_{2}}{\text{279.95 K}}\\\\\text{6.78 L} & = & \text{1.429V}_{2}\\\\V_{2} & = & \textbf{4.7 L}\\\end{array}\\\text{The new volume of the balloon is $\large \boxed{\textbf{4.7 L}}$}$

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3 years ago

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I am a beginner can someone give me a brainliest to start me out I would appreciate it.<br> :)

erastovalidia [21]

Answer:

same

Explanation:

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3 years ago

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