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jekas [21]
3 years ago
7

The name of Earth's single, huge continent from over 250 million years ago is (1 point)

Chemistry
2 answers:
babunello [35]3 years ago
5 0
The answer is pangea.
pochemuha3 years ago
3 0
B. Pangaea or Pangaea Ulitma
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The direction of the electrochemical gradient for Na+ is:
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B. the same as the concentration gradient for Na+

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The net electrochemical gradient movement of potassium is to move into the cytoplasm of the cell, and the net electrochemical gradient of sodium is to move into the extracellular fluid. There is an overall negative net charge inside the cell than compared to the outside because of this

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During a routine check of the fluoride content of Gotham City\'s water supply, the following results were obtained from replicat
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Answer:

The mean is x=0.503\frac{mg}{L}

The 90% confidence interval is:

i_{0.90}=[0.492\frac{mg}{L},0.514\frac{mg}{L}]

Explanation:

1. First organize the data:

x_{1}=0.487

x_{2}=0.487

x_{3}=0.511

x_{4}=0.511

x_{5}=0.519

As there are 5 data, the sample size (n) is n=5

2. Calculate the mean x:

The mean is calculated adding up all the data and divide them between the sample size.

x=\frac{0.511+0.487+0.511+0.487+0.519}{5}

x=0.503\frac{mg}{L}

3. Find 90% confidence interval.

The formula to find the confidence interval is:

i_{0.90}=[x+/-z_{\frac{\alpha}{2}}*(\frac{d}{\sqrt{n}})] (Eq.1)

where x is the mean, d is the standard deviation and n is the sample size.

And

1-\alpha=0.90

\alpha=0.10

\frac{\alpha}{2}=0.05

z_{0.05}=1.645

4. Find the standard deviation

d=\sqrt{\frac{(x_{1}-x)^{2}+(x_{2}-x)^{2}+(x_{3}-x)^{2}+(x_{4}-x)^{2}+(x_{5}-x)^{2}}{n-1}}

d=\sqrt{\frac{(0.487-0.503)^{2}+(0.487-0.503)^{2}+(0.511-0.503)^{2}+(0.511-0.503)^{2}+(0.519-0.503)^{2}}{4}}

d=\sqrt{\frac{(-0.016)^{2}+(-0.016)^{2}+(0.008)^{2}+(0.008)^{2}+(0.016)^{2}}{4}}

d=\sqrt{2.24*10^{-4}}

d=0.015

5. Replace values in (Eq.1):

i_{0.90}=[0.503+/-1.645*(\frac{0.015}{2.236})]

For the addition:

i_{0.90}=[0.503+1.645*(\frac{0.015}{2.236})]

i_{0.90}=0.514

For the subtraction:

i_{0.90}=[0.503-1.645*(\frac{0.015}{2.236})]

i_{0.90}=0.492

The 90% confidence interval is:

i_{0.90}=[0.492,0.514]

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True or False? The nucleus if found inside chromosomes.<br> True<br> False
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