Question

Calculate the number of moles equivalent to 12.7 gram of iodine molecule ​

Answer 1

$\LARGE{ \boxed{ \purple{ \rm{Answer}}}}$

☃️ Chemical formulae ➝ $\sf{I_2}$

How to find?

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

$\boxed{ \sf{No. \: of \: moles = \frac{Given \: weight}{Molecular \: weight} }}$

Solution:

❍ Molecular weight of $\sf{I_2}$

= 2 × 126.90

= 253.80

= 254 (approx.)

❍ Given weight: 12.7

Then, no. of moles,

⇛ No. of moles = 12.7 / 254

⇛ No. of moles = 0.05 moles

⚘ No. of moles of Iodine molecule in the given weight = 0.05 moles

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Answer 2

Answer:

The answer is 0.05 mol

Explanation:

To find the number of moles (n) we use the formula

$n = \frac{m}{M}$

Where

n is the number of moles

m is the mass of the substance

M is the molar mass

To find the number of moles we must first find the molar mass

Since iodine is a diatomic molecule

M( I ) = 127 × 2 = 254 g/mol

Mass of iodine = 12.7 g

So the number of moles in 12.7 g of iodine is

$n = \frac{12.7 \: g}{254 \: g/mol}$

We have the final answer as

n = 0.05 mol

Hope this helps you