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stiks02 [169]
3 years ago
10

Which statement best describes the collisions of gas particles according to the kinetic-molecular theory?

Chemistry
2 answers:
erastovalidia [21]3 years ago
7 0
<span>The statement best describes the collisions of gas particles according to the kinetic-molecular theory is that the collisions of gas particles in an ideal gas are completely elastic. An expansion in the quantity of gas particles in the holder expands the recurrence of impacts with the dividers and in this manner the weight of the gas. The last propose of the motor sub-atomic hypothesis expresses that the normal active vitality of a gas molecule depends just on the temperature of the gas.</span>
aniked [119]3 years ago
5 0

As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy.

hope this helps!

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yawa3891 [41]

Answer:

The greatest acceleration when the unbalanced force is applied will be experienced in :

A) The box with a mass of 2 kg

Explanation:

According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.

F = (Final momentum - initial momentum)/time

or

Force is equal to the product of mass and acceleration

F = m x a

Here a= acceleration

m = mass of the object

If Force is constant then acceleration is inversely proportional to mass

a =\frac{F}{m}

A) The box with a mass of 2kg

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a =\frac{8}{2}

a = 4 m/s2

B) The box with the mass of 4kg

a =\frac{8}{4}

a = 2 m/s2

C) The box with a mass of 6kg

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3 0
3 years ago
The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha
zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

25.9 = x*10.0

25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

m \approx \dfrac{53.3}{6.021}

\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

3 0
3 years ago
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