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stiks02 [169]
3 years ago
10

Which statement best describes the collisions of gas particles according to the kinetic-molecular theory?

Chemistry
2 answers:
erastovalidia [21]3 years ago
7 0
<span>The statement best describes the collisions of gas particles according to the kinetic-molecular theory is that the collisions of gas particles in an ideal gas are completely elastic. An expansion in the quantity of gas particles in the holder expands the recurrence of impacts with the dividers and in this manner the weight of the gas. The last propose of the motor sub-atomic hypothesis expresses that the normal active vitality of a gas molecule depends just on the temperature of the gas.</span>
aniked [119]3 years ago
5 0

As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy.

hope this helps!

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yarga [219]

Answer: it’s D

Explanation:

3 0
2 years ago
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The value of Ka for nitrous acid (HNO2) at 25 ∘C is 4.5×10−4 .a. Write the chemical equation for the equilibrium that correspond
kvv77 [185]

Answers and Explanation:

a)- The chemical equation for the corresponden equilibrium of Ka1 is:

2. HNO2(aq)⇌H+(aq)+NO−2

Because Ka1 correspond to a dissociation equilibrium. Nitrous acid (HNO₂) losses a proton (H⁺) and gives the monovalent anion NO₂⁻.

b)- The relation between Ka and the free energy change (ΔG) is given by the following equation:

ΔG= ΔGº + RT ln Q

Where T is the temperature (T= 25ºc= 298 K) and R is the gases constant (8.314 J/K.mol)

At the equilibrium: ΔG=0 and Q= Ka. So, we can calculate ΔGº by introducing the value of Ka:

⇒ 0 = ΔGº + RT ln Ka

   ΔGº= - RT ln Ka

   ΔGº= -8.314 J/K.mol x 298 K x ln (4.5 10⁻⁴)

  ΔGº= 19092.8 J/mol

c)- According to the previous demonstation, at equilibrium ΔG= 0.

d)- In a non-equilibrium condition, we have Q which is calculated with the concentrations of products and reactions in a non equilibrium state:

ΔG= ΔGº + RT ln Q

Q= ((H⁺) (NO₂⁻))/(HNO₂)

Q= ( (5.9 10⁻² M) x (6.7 10⁻⁴ M) ) / (0.21 M)

Q= 1.88 10⁻⁴

We know that   ΔGº= 19092.8 J/mol, so:

ΔG= ΔGº + RT ln Q

ΔG= 19092.8 J/mol + (8.314 J/K.mol x 298 K x ln (1.88 10⁻⁴)

ΔG= -2162.4 J/mol

Notice that ΔG<0, so the process is spontaneous in that direction.

6 0
3 years ago
How many moles are in 213 mg of calcium fluoride, CaF2?
lana [24]

Answer:

2.73

Explanation:

2.72815277835894

i used an online converter lol it is much faster. if you'd like a step by step guide comment and ill give you one :)

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2 years ago
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Phosphorus has three isotopes, 31p, 32p, and 33p. the atomic number of phosphorus is 15. how many protons does each of the isoto
klemol [59]
<span>For isotopes of any element, the number of protons remains the same, BUT the number of neutrons changes. Since each of the isotopes listed is phosphorus, All three have 15 protons. (They have 16, 17 and 18 protons respectively.)</span>
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Is it true or false I need help.
dsp73

Answer:

true

Explanation:

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