1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kazeer [188]
3 years ago
5

What would be the diameter of the earth if it had the density of a neurton star

Physics
1 answer:
Marat540 [252]3 years ago
5 0
The entire mass of the Earth at neutron star density would fit into a sphere of 305 m in diameter
You might be interested in
A continuous length of wire is made into 10 coaxial loops, located in the plane of this page. Each loop has a cross sectional ar
AleksandrR [38]

Answer:

e = 10 V

Explanation:

given,

number of the coaxial loops = 10

Cross sectional area =  0.5 m²

magnitude of magnetic field =

B = 3 T + (2 T/s)*t.

B = ( 3+ 2 t ) T

induced potential difference = ?

At time = 2 s

we know,

induced emf

e = - N\dfrac{d\phi}{dt}

∅ = B . A

e = - N\dfrac{d(BA)}{dt}

e = - NA\dfrac{dB}{dt}

e = - 10 \times 0.5 \times \dfrac{d}{dt}(3 + 2 t)

e = - 10 \times 0.5 \times 2

e = -10 V

magnitude of induced emf

|e| = |-10 V|

e = 10 V

the induced potential difference in the loop = e = 10 V

7 0
3 years ago
A worker exerts a pulling force on a box. The worker exerts this force by attaching a rope to the box and pulling on the rope so
shusha [124]

Answer:

<em>The magnitude of the pulling force is 20.66% of the gravitational force acting on the box</em>

Explanation:

<u>Accelerated Motion</u>

The net force exerted on a body is the (vector) sum of all forces applied to the body. The net force can be decomposed in its rectangular components and the dynamics of the body can be studied in each direction x,y separately.

Let's start off by calculating the acceleration the worker gives to the box when pulling it. The distance traveled by the box initially at rest in a time t at an acceleration a is given by

\displaystyle x=\frac{at^2}{2}

Solving for a

\displaystyle a=\frac{2x}{t^2}

\displaystyle a=\frac{2\cdot 10}{5.12^2}

a=0.763\ m/s^2

Now we analyze the geometric of the forces applied to the box. Please refer to the free body diagram provided below.

The forces in the y-axis must be in equilibrium since no movement takes place there, thus, being g the acceleration of gravity:

T_y+N=m.g

There Ty is the vertical component of the tension of the rope, N is the normal force, and m is the mass of the box

The decomposition of T gives us

T_y=Tsin\theta

T_x=Tcos\theta

Solving the above equation for N

Tsin\theta+N=m.g

N=m.g-Tsin\theta\text{..........[1]}

Now for the x-axis, there are two forces acting on the box, the x-component of the tension and the friction force Fr. Those forces are not equilibrated, thus acceleration is produced:

Tcos\theta-F_r=m.a

Recalling that

F_r=\mu N

Tcos\theta-\mu N=m.a

Replacing N from [1]

Tcos\theta-\mu (m.g-Tsin\theta)=m.a

Operating

Tcos\theta-\mu m.g+\mu Tsin\theta=m.a

Solving for T

T(cos\theta+\mu sin\theta)=m.a+\mu m.g

\displaystyle T=\frac{m.a+\mu m.g}{cos\theta+\mu sin\theta}

\displaystyle T=m\frac{a+\mu g}{cos\theta+\mu sin\theta}

We don't know the value of m, thus we'll plug in the rest of the data

\displaystyle T=m\frac{0.763+0.10\cdot 9.8}{cos36.8^o+0.10 sin36.8^o}

T=2.0252m

Dividing by the weight of the box m.g

T/(m.g)=2.0252/9.8=0.2066

Thus, the magnitude of the pulling force is 20.66% of the gravitational force acting on the box

7 0
3 years ago
Tech a says that the pcv system recirculates exhaust gases into the intake manifold. tech b says that the pcv system recirculate
d1i1m1o1n [39]

Tech a says that the pcv system recirculates exhaust gases into the intake manifold called Reconstruction debate that had federalism debate that had been an issue since the 1790s.

Reconstruction failed by most other measures: Radical Republican legislation ultimately failed to protect former slaves from white persecution and failed to engender recirculates changes to the social fabric of the South. When President Rutherford B. federalism debate that had been an issue since the 1790s almost mediately . Hayes removed federal troops from the South in 1877, former recirculates officials and slave returned to With the support of a conservative Supreme Court, these newly empowered white southern politicians passed black codes, voter qualifications, and other anti-progressive legislation to reverse the rights that blacks had gained during Radical Reconstruction. The U.S. Supreme Court bolstered this federalism anti-progressive movement federalism  with decisions in the Slaughterhouse Cases, the Civil Rights Cases, and United States v.

Learn more about Reconstruction on:

brainly.com/question/24761999

#SPJ4

5 0
1 year ago
Sound waves travel faster through air than through solids.<br> a. True<br> b. False
WINSTONCH [101]
I believe the answer is true
7 0
3 years ago
A ballast is dropped from a stationary hot-air balloon that is at an altitude of 576 ft. Find (a) an expression for the altitude
Nadya [2.5K]

Answer:

<h2>a) S = \frac{1}{2}gt^2\\</h2><h2>b) 6secs</h2><h2>c) 192ft</h2>

Explanation:

If a ball dropped from a stationary hot-air balloon that is at an altitude of 576 ft, an expression for the altitude of the ballast after t seconds can be expressed using the equation of motion;

S = ut + \frac{1}{2}at^{2}

S is the altitude of the ballest

u is the initial velocity

a is the acceleration of the body

t is the time taken to strike the ground

Since the body is dropped from a stationary air balloon, the initial velocity u will be zero i.e u = 0m/s

Also, since the ballast is dropped from a stationary hot-air balloon, the body is under the influence of gravity, the acceleration will become acceleration due to gravity i.e a = +g

Substituting this values into the equation of the motion;

S = 0 + \frac{1}{2}gt^2\\ S = \frac{1}{2}gt^2\\

a) An expression for the altitude of the ballast after t seconds is therefore

S = \frac{1}{2}gt^2\\

b) Given S = 576ft and g = 32ft/s², substituting this into the formula in (a);

576 = \frac{1}{2}(32)t^2\\\\\\576*2 = 32t^2\\1152 = 32t^2\\t^2 = \frac{1152}{32} \\t^2 = 36\\t = \sqrt{36}\\ t = 6.0secs

This means that the ballast strikes the ground after 6secs

c) To get the velocity when it strikes the ground, we will use the equation of motion v = u + gt.

v = 0 + 32(6)

v = 192ft

7 0
4 years ago
Other questions:
  • Why are new scientific models developed?
    15·2 answers
  • How energy is transferred in a appliance
    6·1 answer
  • a car travels 30.25 kilometers due west and then drives 7.50 kilometers up a hill that inclines 15.0 degrees. what is the vertic
    13·1 answer
  • A liquid is flowing through a horizontal pipe whose radius is m. The pipe bends straight upward through a height of 10.6 m and j
    14·1 answer
  • Which element has a full valence shell of electrons?
    15·2 answers
  • Find the drift velocity of conduction electrons in a gold wire of diameter 2.40 mm 2.40 mm when a current of 0.373 A 0.373 A flo
    9·1 answer
  • When I double displacement reaction takes place, one of the products must be_______.
    6·2 answers
  • If you applied a force of 200 Newtons to lift a box 2.20 meters above the floor, how much work would you be doing?
    6·1 answer
  • Pls help i’ll give brainliest if you give a correct answer!!
    11·2 answers
  • A volleyball flying through the air what type of energy is it?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!