A train has a constant velocity of 2 m/s east. What is the magnitude of the horizontal acceleration of the train?
1 answer:
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Answer:
The range of the bullet is 0.435 kilometers.
Explanation:
According to the problem, maximum height is equal to the range of the bullet. That is:
Where:
- Range of the bullet, measured in meters.
- Maximum height of the bullet, measured in meters.
By the Principle of Energy Conservation, gravitational potential energy reaches its maximum at the expense of the initial kinetic energy. That is to say:
Where:
- Kinetic energy at point 1, measured in joules.
- Gravitational potential energy at point 2, measured in joules, and:
Where:
- Mass of the bullet, measured in kilograms.
- Gravitational constant, measured in meters per square second.
The maximum height is now cleared:
If ,
and
, the maximum height is now computed:
Lastly, the range of the bullet is 0.435 kilometers.