To solve for the weighted average atomic weight of X, all
we have to do is to calculate for the contribution of each isotope. The
contribution of each isotope on the atomic weight of x is calculated by
multiplying their respective atomic weights with the abundance, therefore:
X – 28 = 27.977 amu * (92.23 / 100)
X – 28 = 25.803 amu
X – 29 = 28.976 amu * (4.67 / 100)
X – 29 = 1.353 amu
X – 30 = 29.974 amu * (3.10 / 100)
X – 30 = 0.929 amu
Hence:
X = X – 28 + X – 29 + X – 30
X = 25.803 amu + 1.353 amu + 0.929 amu
<span>X = 28.085 amu</span>
The final speed of the toy car at the end of the given time period is 3.58 m/s.
The given parameters;
- distance traveled by the car, s = 1.2 m
- time of motion of the car, t = 0.67 s
- initial velocity of the car, u = 0
The acceleration of the car is calculated as;

The final velocity of the toy car is calculated as;

Thus, the final speed of the toy car at the end of the given time period is 3.58 m/s.
Learn more here: brainly.com/question/20352766
A wave with a large amplitude
a wave check
Answer:
a) 
b) 
c) 
d) 
Explanation:
Average translation kinetic energy (
) is given as
....................(1)
where,
k = Boltzmann's constant ; 1.38 × 10⁻²³ J/K
T = Temperature in kelvin
a) at T = 27.8° C
or
T = 27.8 + 273 = 300.8 K
substituting the value of temperature in the equation (1)
we have

b) at T = 143° C
or
T = 143 + 273 = 416 K
substituting the value of temperature in the equation (1)
we have

c ) The translational kinetic energy per mole of an ideal gas is given as:

here
= Avagadro's number; ( 6.02×10²³ )
now at T = 27.8° C


d) now at T = 143° C


1. True
2. False
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