Answer:
<em>A) Beam B carries twice as many photons per second as beam A.</em>
Explanation:
If we have two waves with the same wavelength, then their intensity is proportional to their power, or the energy per unit time.
We also know that the amount of photon present in an electromagnetic beam is proportional to the energy of the beam, hence the amount of beam per second is proportional to the power.
With these two facts, we can say that the intensity is a measure of the amount of photon per second in an electromagnetic beam. So we can say that <em>beam B carries twice as more power than beam A, or Beam B carries twice as many photons per second as beam A.</em>
The dimension of K is M/ T^2
according to the question T=2π square root ofm/k here 2 pi is constant so
T= root of m /k and root of k = root of m/ T now by squaring on both the sides we get the answer k= M/ T^2
complete question :
A spring is hanging down from the ceiling, and an object of mass m is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T=√2πm/k, where k is known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct?
To learn more about dimension:
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Answer:
6.20×10⁴ V/m
Explanation:
The magnitude of electric field is:
E = √(Eₓ² + Eᵧ²)
where Eₓ = ∂φ/∂x and Eᵧ = ∂φ/∂y.
φ = 1.11 (x² + y²)^-½ − 429x
Eₓ = -0.555 (x² + y²)^-(³/₂) (2x) − 429
Eᵧ = -0.555 (x² + y²)^-(³/₂) (2y)
Evaluating at (0.003, 0.003):
Eₓ = -44034 V/m
Eᵧ = -43605 V/m
The magnitude is:
E = 61971 V/m
Rounded to three significant figures, the strength of the electric field is 6.20×10⁴ V/m.
Answer:
xtotal = 90km
displacement = 18km N
Explanation:
To find the total distance traveled by the car, you first calculate the distance traveled by the car when it travels to north. You use the following formula:
(1)
x: distance
v: speed of the car = 30 m/s
t: time = one half hour
In order to calculate the distance you convert the time from hours to seconds:

Then, you replace the values of t and v in the equation (1):
(2)
Next, you calculate the distance traveled by the car when it travels to south:

You convert the time from minutes to seconds:


Finally, you sum both distances x and x':

The total distance traveled by the car is 90km
The total displacement is the final distance of the car respect to the starting point of the motion. This is calculated by subtracting x' to x:

The total displacement of the car is 18km to the north from its starting point of motion.
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