All categories

2 years ago

What is the range of the fallowing numbers 29, 47, 32, 36, 57, 20, 39, 38, 52, 51, 28, 24, 44, 40, 45, 35, 50, 50, 32, 31

Mathematics

2 answers:

Jlenok [28]2 years ago

6 0

Answer:

Step-by-step explanation:

First of all, let's define what range is. The range is the highest value of a set of numbers minus the lowest value of the same set. In this case, your highest value is 57 and your lowest value is 20. The sum would be 57 - 20 which would equal 37 and that is your answer.

Hope I helped you out :)

Lunna [17]2 years ago

4 0

Answer: 37

Step-by-step explanation:

range = max - min

max = maximum value in a data set

min = minimum value in a data set

Maximum value: 57

Minimum value: 20

Range: 37

You might be interested in

20 PTS!!!!!!!! HELPPP

Oksi-84 [34.3K]

Answer:

1. Not congruent

2. Not congruent

3. Congruent

4. Congruent

5. Not congruent

6. Not congruent

???

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If U = {a, b, c, d, e, f, g, h}, A= {a, b, c, d, e) and B= {c, d, e, f, g), find A-B and A nB.

Assoli18 [71]

U = {a, b, c, d, e, f, g, h}, A= {a, b, c, d, e) and B= {c, d, e, f, g),

now,

A-B = {a,b}

A n B = { c,d,e}

3 0

3 years ago

When studying radioactive material, a nuclear engineer found that over 365 days,

Gnom [1K]

Answer:

a) The mean number of radioactive atoms that decay per day is 81.485.

b) 0% probability that on a given day, 50 radioactive atoms decayed.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\lambda$ is the mean in the given interval.

a. Find the mean number of radioactive atoms that decayed in a day.

29,742 atoms decayed during 365 days, which means that:

$\lambda = \frac{29742}{365} = 81.485$

The mean number of radioactive atoms that decay per day is 81.485.

b. Find the probability that on a given day, 50 radioactive atoms decayed.

This is P(X = 50). So

$P(X = 50) = \frac{e^{-81.485}*(81.485)^{50}}{(50)!} = 0$

0% probability that on a given day, 50 radioactive atoms decayed.

5 0

2 years ago

13 units find area of sector EFG.

s2008m [1.1K]

Answer:

picture? (170

Step-by-step explanation:

5 0

3 years ago

Direction if parabola. x2?6x+8=yx2-6x+8=y

STatiana [176]

{\text{Direction of parabola depends on the sign of quadratic coefficient of a }} \hfill \\

{\text{quadratic equation}}. \hfill \\

{\text{For given quadratic equation}}. \hfill \\

a{x^2} + bx + c = 0 \hfill \\

{\text{The parabola is in the upward direction if }}a{\text{ }} > {\text{ }}0{\text{ and in downward direction if }}a < 0 \hfill \\

{\text{Here, the equation of given parabola is }} \hfill \\

{x^2} - 6x + 8 = y \hfill \\

\Rightarrow y = \left( {{x^2} - 6x + 9} \right) - 9 + 8 \hfill \\

\Rightarrow y = {\left( {x - 3} \right)^2} - 1. \hfill \\

{\text{Thus, the parabola is in the upward direction}} \hfill \\

8 0

3 years ago