Answer:
The expected value of the safe bet equal $0
Step-by-step explanation:
If
is a finite numeric sample space and
for k=1, 2,..., n
is its probability distribution, then the expected value of the distribution is defined as
What is the expected value of the safe bet?
In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is
S = {100,-100}
Since the coin is supposed to be fair,
P(X=100)=0.5
P(X=-100)=0.5
and the expected value is
E(X) = 100*0.5 - 100*0.5 = 0
Answer:
1.6%
Step-by-step explanation:
The cumulative distribution function (CDF) of a random variable X is denoted by F(x), and is defined as
F(x) = P(X ≤ x). where x is the largest possible value of X that is less than or equal to x
z = (x-μ)/σ,
where:
x is the raw score = 205
μ is the population mean, = 220 pounds
σ is the population standard deviation = 7 pounds
205 -220/7
z = -15/7
z = -2.1428571429
Using the normal cdf function on your graphing calculator,the cumulative distribution is
normalcdf( -2.1428571429, 100)
= 0.01606229
In percent form = 0.01606229 × 100
= 1.6%
Answer:
24
Step-by-step explanation:
56/7=8
8x3=24
Answer:
she is wrong because 1800/9 is 200.
