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xxMikexx [17]
2 years ago
12

I need help with this one

Mathematics
1 answer:
docker41 [41]2 years ago
5 0

Just put the options in the inequalities and check if they are true or not :

A ) ( - 1 , 0 )

2x + y \leqslant 3

2( - 1) + 0 \leqslant 3

- 2 \leqslant 3 \:  \:  \: kinda \: true

And

x - y <  - 3

- 1 - 0 <  - 3

- 1 <  - 3 \:  \:  \: false

Thus A is wrong

_____________________________________________

B ) ( - 1 , - 1 )

2( - 1) + ( - 1) \leqslant 3

- 2 - 1 \leqslant 3

- 3 \leqslant  3 \:  \: kinda \: true

And

- 1 - ( - 1)  <  - 3

- 1 + 1<  - 3

0 <  - 3 \:  \:  \: false

Thus B is wrong

_____________________________________________

C ) ( - 2 , 4 )

2( - 2) + 4 \leqslant   3

- 4 + 4 \leqslant  3

0 \leqslant  3 \:  \: kinda \: true

And

- 2 - 4 <  - 3

- 6 <  - 3 \:  \:  \: true

Thus C is the correct option

_____________________________________________

U can do D urself ...

Have a great day ♡

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Step-by-step explanation:

Distribute the numbers -2 and 3...

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