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WINSTONCH [101]
3 years ago
9

Help me if you can please?? and thanks! :)))​

Mathematics
1 answer:
Vaselesa [24]3 years ago
4 0

Answer:

<em><u>0.0095</u></em>

Step-by-step explanation:

= 0.009455 ( as they are bigger than 4 )

= 0.0095

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A town map has a scale of 2cm:0.5km what is the actual distance for a walk measured at 9cm on the map?
Nastasia [14]

Answer: 2.25 km

Step-by-step explanation:

2 cm = 0.5 km

9 cm = (9 x 0.5)/2

= 2.25 km

4 0
4 years ago
Read 2 more answers
A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0
3 years ago
How wide and how long is the actual swimming pool
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ig 50 meters long by 25 meters wide

Step-by-step explanation:

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Convert the rate of 10 yards per minutes to feet per hour
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Which of the following inequalities represent the number line below?
MrRissso [65]

Answer:

greater than or equal to 250

x < or = 250

Step-by-step explanation:

hopefully this helps

6 0
3 years ago
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